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ad-work [718]
3 years ago
8

I need help on number 3

Mathematics
2 answers:
TiliK225 [7]3 years ago
5 0
Divide 17.5 by 0.07
;;;;;;;;;;
mrs_skeptik [129]3 years ago
4 0
The answer is 17.5 ÷ .07 = 250 seconds.
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Alyssa said that 6/8 and 9/12 are not equivalent because there's no whole number you can multiply both parts of 6/8 by to get 9/
luda_lava [24]
No. 6/8=9/12
by multiplying the denominators you get the common denominator of 72
then multiply each numerator by the number of the opposite denominator
8x12=96
6x12=72
9x8=72
Therefore, 72/96=72/96
                   (6/8   = 9/12)
5 0
3 years ago
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A forestry company hopes to generate credits from the carbon sequestered in its plantations.The equation describing the forest w
Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

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6 0
1 year ago
3. Sandy's Sweets sells cookies for $1.50 cach while Barbara's Bakery sells cookies for $2.10 each. After
Anna11 [10]

Answer:

5 times

11.50

plz give brainiest

Step-by-step explanation:

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2 years ago
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OverLord2011 [107]

Answer:

you can do a diagram representing this product by drawing a box with six squares and then putting three lines for each box and divide 3÷3 and you will get 5

6 0
2 years ago
A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .
insens350 [35]
<h2>Answer:0.2352m</h2>

Step-by-step explanation:

Let the mass of the person be m.

Let the spring constant be k.

Let the displacement in spring be x

Let the acceleration due to gravity be g

As it is given that the person just stands,the forces are balanced.

So,mg=kx

Given,

m=60Kg\\k=2500Nm^{-1}\\g=9.8ms^{-2}

60\times 9.8=2500\times x\\x=\frac{588}{2500}=0.2352m

6 0
2 years ago
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