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ad-work [718]
3 years ago
8

I need help on number 3

Mathematics
2 answers:
TiliK225 [7]3 years ago
5 0
Divide 17.5 by 0.07
;;;;;;;;;;
mrs_skeptik [129]3 years ago
4 0
The answer is 17.5 ÷ .07 = 250 seconds.
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PLEASE HELP ASAP PLLSSS!!!!
IgorC [24]

Answer:

  • 7 months

Step-by-step explanation:

a)

  • A(x) = 275 + 125x

b)

  • C(x) = 1850 - 100x

c)

  • 275 + 125x = 1850 - 100x
  • 125x + 100x = 1850 - 275
  • 225x = 1575
  • x = 1575 / 225
  • x = 7

The answer is 7 months

4 0
2 years ago
Find the total surface area of the following cylinder: r=3 cm 3 cm SA = [? ]n cm2
OLga [1]

Answer:

<u>36</u>

Step-by-step explanation:

5 0
2 years ago
You ask 200 randomly chosen students to name their favorite ice cream flavor. There are 1800 students in the school. Based on th
Kaylis [27]

Answer:

351

Step-by-step explanation:

Complete question :

Vanilla= 36

Chocolate=21

Strawberry=24

Chocolate Chip=39

SOLUTION:

39 chocolate chip to 200 students = x chocolate chip to 1800 students

39/200 = x / 1800

Solving for 'x'

(200)(x) = (39)(1800)

200x = 70200

x = 70200/200

x = 351

OR

39 out of 200 picked chocolate chip

therefore, 39/200 = 0.195 = 19.5%  ( 32.5% chose chocolate chip)

19.5% of 1800 = 0.195(1800) = 351 students

6 0
3 years ago
Part B
alisha [4.7K]

Question:

Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment  AC represent the base of the triangle.

(a)  Find the equation of the line passing through B and perpendicular to the line AC

(b)  Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.

Answer:

y = \frac{1}{5}x + \frac{12}{5}

D = (\frac{43}{26},\frac{71}{26})

Step-by-step explanation:

Given

\triangle ABC

A = (2,1)

B = (3,3)

C = (1,6)

Solving (a): Line that passes through B, perpendicular to AC.

First, calculate the slope of AC

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

A = (2,1) --- (x_1,y_1)

C = (1,6) --- (x_2,y_2)

The slope is:

m = \frac{6- 1}{1 - 2}

m = \frac{5}{-1}

m = -5

The slope of the line that passes through B is calculated as:

m_2 = -\frac{1}{m} --- because it is perpendicular to AC.

So, we have:

m_2 = -\frac{1}{-5}

m_2 = \frac{1}{5}

The equation of the line is the calculated using:

m_2 = \frac{y_2 - y_1}{x_2 - x_1}

Where:

m_2 = \frac{1}{5}

B = (3,3) --- (x_1,y_1)

(x_2,y_2) = (x,y)

So, we have:

\frac{1}{5} = \frac{y - 3}{x - 3}

Cross multiply

5(y-3) = 1(x - 3)

5y - 15 = x - 3

5y  = x - 3 + 15

5y  = x +12

Make y the subject

y = \frac{1}{5}x + \frac{12}{5}

Solving (b): Point of intersection between AC and y = \frac{1}{5}x + \frac{12}{5}

First, calculate the equation of AC using:

y = m(x - x_1) + y_1

Where:

A = (2,1) --- (x_1,y_1)

m = -5

So:

y=-5(x - 2) + 1

y=-5x + 10 + 1

y=-5x + 11

So, we have:

y=-5x + 11 and y = \frac{1}{5}x + \frac{12}{5}

Equate both to solve for x

i.e.

y = y

-5x + 11 = \frac{1}{5}x + \frac{12}{5}

Collect like terms

-5x -\frac{1}{5}x = \frac{12}{5} - 11

Multiply through by 5

-25x-x = 12 - 55

Collect like terms

-26x = -43

Solve for x

x = \frac{-43}{-26}

x = \frac{43}{26}

Substitute x = \frac{43}{26} in y=-5x + 11

y = -5 * \frac{43}{26} + 11

y =  \frac{-5 *43}{26} + 11

Take LCM

y =  \frac{-5 *43+11 * 26}{26}

y =  \frac{71}{26}

Hence, the coordinates of D is:

D = (\frac{43}{26},\frac{71}{26})

3 0
2 years ago
Evaluate-4/1/3-2+7/5/6
kirza4 [7]
Compute the division left to right first, and then the addition/subtraction left to right!
8 0
3 years ago
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