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3 years ago

I need help on number 3

Mathematics

2 answers:

TiliK225 [7]3 years ago

5 0

Divide 17.5 by 0.07
;;;;;;;;;;

mrs_skeptik [129]3 years ago

4 0

The answer is 17.5 ÷ .07 = 250 seconds.

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PLEASE HELP ASAP PLLSSS!!!!

IgorC [24]

Answer:

7 months

Step-by-step explanation:

A(x) = 275 + 125x

C(x) = 1850 - 100x

275 + 125x = 1850 - 100x
125x + 100x = 1850 - 275
225x = 1575
x = 1575 / 225
x = 7

The answer is 7 months

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2 years ago

Find the total surface area of the following cylinder: r=3 cm 3 cm SA = [? ]n cm2

OLga [1]

Answer:

<u>36</u>

Step-by-step explanation:

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2 years ago

You ask 200 randomly chosen students to name their favorite ice cream flavor. There are 1800 students in the school. Based on th

Kaylis [27]

Answer:

351

Step-by-step explanation:

Complete question :

Vanilla= 36

Chocolate=21

Strawberry=24

Chocolate Chip=39

SOLUTION:

39 chocolate chip to 200 students = x chocolate chip to 1800 students

39/200 = x / 1800

Solving for 'x'

(200)(x) = (39)(1800)

200x = 70200

x = 70200/200

x = 351

39 out of 200 picked chocolate chip

therefore, 39/200 = 0.195 = 19.5% ( 32.5% chose chocolate chip)

19.5% of 1800 = 0.195(1800) = 351 students

6 0

3 years ago

Part B

alisha [4.7K]

Question:

Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment AC represent the base of the triangle.

(a) Find the equation of the line passing through B and perpendicular to the line AC

(b) Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.

Answer:

$y = \frac{1}{5}x + \frac{12}{5}$

$D = (\frac{43}{26},\frac{71}{26})$

Step-by-step explanation:

Given

$\triangle ABC$

$A = (2,1)$

$B = (3,3)$

$C = (1,6)$

Solving (a): Line that passes through B, perpendicular to AC.

First, calculate the slope of AC

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$A = (2,1)$ --- $(x_1,y_1)$

$C = (1,6)$ --- $(x_2,y_2)$

The slope is:

$m = \frac{6- 1}{1 - 2}$

$m = \frac{5}{-1}$

$m = -5$

The slope of the line that passes through B is calculated as:

$m_2 = -\frac{1}{m}$ --- because it is perpendicular to AC.

So, we have:

$m_2 = -\frac{1}{-5}$

$m_2 = \frac{1}{5}$

The equation of the line is the calculated using:

$m_2 = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$m_2 = \frac{1}{5}$

$B = (3,3)$ --- $(x_1,y_1)$

$(x_2,y_2) = (x,y)$

So, we have:

$\frac{1}{5} = \frac{y - 3}{x - 3}$

Cross multiply

$5(y-3) = 1(x - 3)$

$5y - 15 = x - 3$

$5y = x - 3 + 15$

$5y = x +12$

Make y the subject

$y = \frac{1}{5}x + \frac{12}{5}$

Solving (b): Point of intersection between AC and $y = \frac{1}{5}x + \frac{12}{5}$

First, calculate the equation of AC using:

$y = m(x - x_1) + y_1$

Where:

$A = (2,1)$ --- $(x_1,y_1)$

$m = -5$

So:

$y=-5(x - 2) + 1$

$y=-5x + 10 + 1$

$y=-5x + 11$

So, we have:

$y=-5x + 11$ and $y = \frac{1}{5}x + \frac{12}{5}$

Equate both to solve for x

i.e.

$y = y$

$-5x + 11 = \frac{1}{5}x + \frac{12}{5}$

Collect like terms

$-5x -\frac{1}{5}x = \frac{12}{5} - 11$

Multiply through by 5

$-25x-x = 12 - 55$

Collect like terms

$-26x = -43$

Solve for x

$x = \frac{-43}{-26}$

$x = \frac{43}{26}$

Substitute $x = \frac{43}{26}$ in $y=-5x + 11$

$y = -5 * \frac{43}{26} + 11$

$y = \frac{-5 *43}{26} + 11$

Take LCM

$y = \frac{-5 *43+11 * 26}{26}$

$y = \frac{71}{26}$

Hence, the coordinates of D is:

$D = (\frac{43}{26},\frac{71}{26})$

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2 years ago

Evaluate-4/1/3-2+7/5/6

kirza4 [7]

Compute the division left to right first, and then the addition/subtraction left to right!

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3 years ago