The quality or state of being volcanic.
Answer:
[H₂SO₄] = 6.07 M
Explanation:
Analyse the data given
8.01 m → 8.01 moles of solute in 1kg of solvent.
1.354 g/mL → Solution density
We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g
Mass of solvent = 1kg = 1000 g
Mass of solution = 1000g + 785.4 g = 1785.4 g
We apply density to determine the volume of solution
Density = Mass / volume → Volume = mass / density
1785.4 g / 1.354 g/mL = 1318.6 mL
We need this volume in L, in order to reach molarity:
1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L
Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M
Answer:
Enantiomers
Chiral
Yes they will be formed in equal amount.
Explanation:
The Two possible stereo isomers are formed due to generation a chiral center in the molecule.
There will be a carbon with all the four groups different.
The two isomers will be called as enantiomers, which are non super-imposable mirror image of each other.
They are named as "R" or "S'" based on the selection rule.
The IUPAC names are also given in the figure.
The two isomers will be formed in equal amount as during photochemical chloriantion of a compound free radicals are generated (which are trigonal planar) and the other radical may attack from either side (front side or back side) giving the two stereo-isomers.
Answer:
1.25 moles of tungsten carbide
Explanation:
Tungsten carbide, WC, is a substance that is produced prom carbon and tungsten as follows:
W + C → WC
Based on the reaction, 1 mole of Carbon produce 1 mole of tungsten carbide. That means if 1.25 moles of carbon are added in excess of tungsten, the moles of tungsten carbide produced are:
<h3>1.25 moles of tungsten carbide</h3>
Answer:
From the numerical steps highlighted under explanation, the average atomic mass of bromine is 79.91 u
Explanation:
The steps to be taken will involve;
1) Find the number of isotopes of bromine.
2) Identify the atomic mass and relative abundance of each of the isotopes.
3) Multiply the atomic mass of each of the isotopes by their corresponding values relative abundance value.
4) Add the value in step 3 above to get the average atomic mass of bromine.
Now;
Bromine has 2 isotopes namely;
Isotope 1: Atomic mass = 78.92amu and a relative abundance of 50.69%.
Isotope 2: Atomic mass = 80.92amu and a relative abundance of 49.31%.
Using step 3 above, we have;
(78.92 × 50.69%)
And (80.92 × 49.31%)
Using step 4 above, we have;
(78.92 × 50.69%) + (80.92 × 49.31%) ≈ 79.91 u
