1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natita [175]
3 years ago
5

Calculate the mass of sodium phosphate in aqueous solution to fully react with 37 g of chromium nitrate(III) an aqueous solution

?(report answer in grams and only three Sigg figs do not put the unit)
Chemistry
1 answer:
Alla [95]3 years ago
4 0

Answer:

41 g

Explanation:

The equation of the reaction is;

Cr(NO3)3(aq)+Na3PO4(aq)=3NaNO3(s)+CrPO4(aq)

Number of moles of chromium nitrate = 37g/ 146.97 g/mol = 0.25 moles

1 mole of sodium phosphate reacts with 1 mole of chromium nitrate

x moles of sodium phosphate react as with 0.25 moles of chromium nitrate

x= 1 × 0.25/1

x= 0.25 moles

Mass of sodium phosphate = 0.25 moles × 163.94 g/mol

Mass of sodium phosphate = 41 g

You might be interested in
Consider the gaseous reaction: A(g) + B(g) → AB(g) A mixture of 0.04 mol of gas A and 0.1 mole of gas B was allowed to react at
Igoryamba

Answer:

The total pressure of the mixture is 2.5 atm.

Explanation:

According to Dalton´s law of partial pressures, the total pressure of the mixture is the sum of the partial pressures of each gas.

From the chemical equation, we know that 1 mol of A reacts with 1 mol of B to produce 1 mol of AB. We have only 0.04 mol of gas A, then, only 0.04 mol of AB will be produced when reacting with 0.04 mol of B. 0.06 mol of B will remain without reacting.

After the reaction, there will be 0.04 mol of AB and 0.06 mol of B.

The pressure of AB can be calculated as follows:

PAB = n*R*T / V

Where:

PAB = partial pressure of gas AB.

n = number of mole of AB.

R = gas constant = 0.082 l atm / K mol

T = temperature

V = volume

Then:

PAB = 0.04 mol * 0.082 (l atm / K mol) * 300 K / 1 l = 0.98 atm.

In the same way, the partial pressure of B can be calculated:

PB = 0.06 mol * 0.082 (l atm / K mol) * 300 K / 1 l = 1.5 atm.

The total pressure (Pt) is then:

Pt = PAB + PB = 0.98 atm + 1.5 atm = <u>2.5 atm</u>

5 0
3 years ago
A chemist titrates 60.0 mL of a 0.1935 M benzoic acid (HC (H5CO2) solution with 0.2088 M KOH solution at 25 °C. Calculate the pH
erik [133]

Answer:

pH at the equivalence point is 8.6

Explanation:

A titulation between a weak acid and a strong base, gives a basic pH at the equivalence point. In the equivalence point, we need to know the volume of base we added, so:

mmoles acid = mmoles of base

60 mL . 0.1935M = 0.2088 M . volume

(60 mL . 0.1935M) /0.2088 M = 55.6 mL of KOH

The neutralization is:

HBz + KOH  ⇄  KBz  +  H₂O

In the equilibrum:

HBz + OH⁻   ⇄  Bz⁻  +  H₂O

mmoles of acid are: 11.61 and mmoles of base are: 11.61

So in the equilibrium we have, 11.61 mmoles of benzoate.

[Bz⁻] = 11.61 mmoles / (volume acid + volume base)

[Bz⁻] = 11.61 mmoles / 60 mL + 55.6 mL = 0.100 M

The conjugate strong base reacts:

  Bz⁻  +  H₂O  ⇄  HBz + OH⁻    Kb

0.1 - x                       x        x

(We don't have pKb, but we can calculate it from pKa)

14 - 4.2 = 9.80 → pKb  → 10⁻⁹'⁸ = 1.58×10⁻¹⁰ → Kb

Kb = [HBz] . [OH⁻] / [Bz⁻]

Kb = x² / (0.1 - x)

As Kb is so small, we can avoid the quadratic equation

Kb =  x² / 0.1 → Kb . 0.1 = x²

√ 1.58×10⁻¹¹ = [OH⁻] = 3.98 ×10⁻⁶ M

From this value, we calculate pOH and afterwards, pH (14 - pOH)

- log [OH⁻] =  pOH → - log 3.98 ×10⁻⁶  = 5.4

pH = 8.6

7 0
3 years ago
A sample of CO2 gas at 100 degrees Celsius has a volume of 250 mL at 760 mm Hg. How many moles of CO2 are present
Fed [463]

There are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

HOW TO CALCULATE NUMBER OF MOLES:

The number of moles of a sample of gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure of gas (atm)
  • V = volume (L)
  • n = number of moles (mol)
  • R = gas law constant (0.0821 Latm/molK)
  • T = temperature (K)

According to this question;

  • P = 760mmHg = 1 atm
  • T = 100°C = 100 + 273 = 373K
  • V = 250mL = 0.250L
  • n = ?

1 × 0.250 = n × 0.0821 × 373

0.250 = 30.62n

n = 0.250 ÷ 30.62

n = 8.16 × 10-³mol

Therefore, there are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

Learn more about number of moles at: brainly.com/question/4147359

6 0
3 years ago
Grey Goose ® vodka has an alcohol content of 40.0 % (v/v). Assuming that vodka is composed of only ethanol and water answer the
Vitek1552 [10]

Explanation:

Grey Goose vodka has an alcohol content of 40.0 % (v/v).

Volume of vodka = V = 100 mL

This means that 40.0 mL of alcohol is present 100 mL of vodka.

Volume of ethanol=V' = 40.0 mL

Mass of ethanol = m

Density of the ethanol = d = 0.789 g/mL

m=d\times V' = 0.789 g/ml\times 40.0 mL=31.56 g

Volume of water = V''= 100 ml - 40.0 mL = 60.0 mL

Mass of water = m'

Density of the water = d' = 1.00 g/mL

m'=d'\times V'' = 1.00 g/ml\times 60.0 mL=60.0 g

a.)

Moles of ethanol = n= \frac{31.56 g}{46g/mol}=0.6861 mol

Volume of vodka = V = 100 mL = 0.100 L ( 1mL=0.001 L)

Molarity of the ethanol:

=\frac{0.6861 mol}{0.100 L}=6.861 M

6.861 M the molarity of ethanol in this vodka.

b) Mass of ethanol = 31.56 g

Moles of ethanol = n= \frac{31.56 g}{46g/mol}=0.6861 mol

Volume of vodka = V = 100 mL

Mass of vodka = m

Density of the water = D = 0.935 g/mL

M=D\times V=0.935 g/ml\times 100 ml=93.5 g

The percent by mass of ethanol % (m/m):

\frac{31.56 g}{93.5 g}\times 100=33.75\%

33.75% is the percent by mass of ethanol % (m/m) in this vodka.

c)

Moles of ethanol = n= \frac{31.56 g}{46g/mol}=0.6861 mol

Mass of solvent that is water = 60.0 g = 0.060 kg ( 1g = 0.001 kg)

Molality of ethanol in vodka :

m=\frac{0.6861 mol}{0.060 kg}=11.435 m

11.435 m is the molality of ethanol in this vodka.

d)

Moles of ethanol = n_1=\frac{31.56 g}{46g/mol}=0.6861 mol

Moles of water = n_2=\frac{60.0 g}{18 g/mol}=3.333 mol

Mole fraction of ethanol = \chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.6861 mol}{0.6861 mol+3.333 mol}

= 0.1707

Mole fraction of water = \chi_2

\chi_2=\frac{n_2}{n_1+n_2}=\frac{3.3333 mol}{0.6861 mol+3.333 mol}

= 0.8290

e)

The vapor pressure of vodka = P

Mole fraction of ethanol = \chi_1=0.1707

Mole fraction of water = \chi_2=0.8290

The vapor pressures of ethanol  = p_1=45.0 Torr

The vapor pressures of pure water = p_2=23.8Torr

P=\chi_1\times p_1+\chi_2\times p_2

P=0.1707\times 45.0torr+0.8290\times 23.8 Torr=27.41 torr

The vapor pressure of vodka is 27.41 Torr.

5 0
3 years ago
How many electrons does silver have to give up in order to become an ion?
Naddika [18.5K]
A silver atom has to lose only 1 electron to achieve a <span>pseudo-noble-gas electron configuration.</span>
8 0
3 years ago
Other questions:
  • Why can't we destroy bothersome pollutants by just dissolving in ocean
    11·1 answer
  • water (h2o) and hydrogen peroxide (h2o2) both consist of hydrogen and oxygen atoms. Explain why they have different chemical and
    10·1 answer
  • Help please 20points
    7·2 answers
  • Differences between hypothesis and theory​
    9·2 answers
  • Draw the product of the reaction between 2-pentanol and PBr3. You do not have to consider stereochemistry. You do not have to ex
    12·1 answer
  • You want to go out with me
    12·2 answers
  • What are the properety of covalent bond​
    15·2 answers
  • What is Planck's constant ??​
    9·2 answers
  • How would you describe the kinetic energy of the particles in a solid? 0 low kinetic energy O high kinetic energy same kinetic e
    15·1 answer
  • To study a marine organism, a biologist prepares a 1.00-kg sample to simulate the ion concentrations in seawater. She mixes 26.5
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!