Answer:
1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi
Explanation:
Let's do the required conversions:
1 mol of atoms has 6.02×10²³ atoms
Bi → 1 mol of bismuth weighs 208.98 grams
Let's do the rules of three:
6.02×10²³ atoms are the amount of 1 mol of Bi
4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles
1 mol of Bi weighs 208.98 g
7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g
Volume = (4/3) × π × r^3
R = 1/2 D
R = 7
V = 4/3 x π x 7^3
Exact Form:
1372 π/ 3
Decimal Form:
1436.75504024
Answer:A+B - AB
Element a reaction with element b to create the newest element ab
Answer:
Ionization and dissociation
