<h3>
Answer:</h3>
54.756 g
<h3>
Explanation:</h3>
Assuming the equation for the reaction in question;
3NO₂(g) + H₂O(l) → 2HNO₃(aq) + NO(g)
We are given;
We are required to calculate the mass of HNO₃ produced
- We can calculate the mass of HNO₃ produced using the following simple steps;
<h3>Step 1: Calculate the moles of NO₂</h3>
Moles = Mass ÷ Molar mass
Molar mass of NO₂ = 46.01 g/mol
Therefore;
Moles of NO₂ = 60.0 g ÷ 46.01 g/mol
= 1.304 moles
<h3>Step 2: Calculate the moles of HNO₃ produced </h3>
From the equation, 3 moles of NO₂ reacted to produce 2 mole of HNO₃
Therefore, the mole ratio of NO₂ to HNO₃ is 3 : 2
Thus;
Moles of HNO₃ = Moles of NO₂ × 2/3
= 1.304 moles × 2/3
= 0.869 Moles
<h3>Step 3: Calculate the mass of HNO₃</h3>
Mass = Moles × Molar mass
Molar mass of HNO₃ = 63.01 g/mol
Therefore;
Mass = 0.869 moles × 63.01 g/mol
= 54.756 g
Thus, the mass of HNO₃ produced is 54.756 g
