<h2>see in the attachment hope it helps you</h2>
Answer:
199920J
Explanation:
Given parameters:
Mass of steam = 85g
Unknown:
Heat released when the liquid is condensed = ?
Solution:
The heat released by the substance is given as;
H = mL
H is the heat released
m is the mass
L is the latent heat of steam = 2352J/g
Heat released = 85 x 2352 = 199920J
methanol:
1 mole CH3 OH --> produces --> 1 mole CO2
1 mole CO2 has a molar mass of 44.01 gh/mole
your set up is:
(44.01 g CO2) / -726.5kJ = 0.06058g
your answer 0.06058 grams of CO2 produced per kJ released.
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L
<span>boron trichloride + water → boric acid + hydrochloric acid</span>
