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bulgar [2K]
4 years ago
6

A steam engine generating 5 hp is raising a load weighing 2000 lb.How high will thebload be raised in 10 s.​

Physics
1 answer:
notsponge [240]4 years ago
6 0

Answer:

Explanation:

bi

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PLEASE I NEED HELP
777dan777 [17]

Answer:

K= 95.4 J

Explanation:

For this exercise we must use the conservation of mechanical energy.

We set a reference system on the floor.

Starting point. Higher

          Em₀ = U = m g h

Final point. Just before taking the floor

           Em_f = K = ½ m v²

energy is conserved because there is no friction

         Em₀ = Em_f

         mg h = K

         

The height is

  1.         h = y -y₀

                 h = 0- y₀

let's calculate

       K =  3.23 (-9.81)  (-3.01)          

       K= 95.4 J

5 0
3 years ago
Se tienen 500g de alcohol etílico a una temperatura de -40 °C ¿Cuánto calor se necesita para transformarlo a vapor a una tempera
Feliz [49]

The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?

Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

Explanation:

Given: Mass = 500 g

Initial temperature = -40^{o}C

Final temperature = 150^{o}C

The standard value of specific heat of ethyl alcohol is 2.46 J/g ^{o}C.

Formula used to calculate the heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J

Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

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