Answer:
K= 95.4 J
Explanation:
For this exercise we must use the conservation of mechanical energy.
We set a reference system on the floor.
Starting point. Higher
Em₀ = U = m g h
Final point. Just before taking the floor
Em_f = K = ½ m v²
energy is conserved because there is no friction
Em₀ = Em_f
mg h = K
The height is
- h = y -y₀
h = 0- y₀
let's calculate
K = 3.23 (-9.81) (-3.01)
K= 95.4 J
The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?
Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of
to
.
Explanation:
Given: Mass = 500 g
Initial temperature = 
Final temperature = 
The standard value of specific heat of ethyl alcohol is
.
Formula used to calculate the heat energy is as follows.

where,
q = heat energy
m = mass of substance
C = specific heat
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29%5C%5C%3D%20500%20g%20%5Ctimes%202.46%20J%2Fg%5E%7Bo%7DC%20%5Ctimes%20%5B150%20-%20%28-40%29%5D%5E%7Bo%7DC%5C%5C%3D%20233700%20J)
Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of
to
.