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Julli [10]
3 years ago
6

Which formula is used to find an object's acceleration?

Physics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

4 option is correct ........

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Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.5-m-long hollow tube in the cr
Oksi-84 [34.3K]

Answer:

f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz

Explanation:

lets assume speed of sound is 350 m/s.

frequencies of a standing wave modes of an open-close tube of length L

fm = m(v/4L)

where m is 1,3,5,7......

and fm = mf1

where f1 = fundamental frequency

so therefore: f1 = 350 x 4 / 1.5

f1 = 58.3Hz

f2 = 3 x 58.3

f2 = 175Hz

f3 = 5 x 58.3

f3 = 291.6Hz

5 0
4 years ago
An insulator can do which of the following? Conduct charge through it. Become positively or negatively charged. Transfer protons
ser-zykov [4K]
The correct answer is:
<span>Become positively or negatively charged

In fact, an insulator is a material where charges cannot move freely. Therefore, it can be positively or negatively charge (for example, if it is rubbed against another object, the insulator can remain with an excess of charge), but it cannot transfer charge to other objects.</span>
5 0
3 years ago
What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.
lora16 [44]

Density <em>ρ</em> is mass <em>m</em> per unit volume <em>v</em>, or

<em>ρ</em> = <em>m</em> / <em>v</em>

Solving for <em>v</em> gives

<em>v</em> = <em>m</em> / <em>ρ</em>

So the given object has a volume of

<em>v</em> = (130 g) / (65 g/cm³) = 2 cm³

5 0
3 years ago
Calculate the potential energy of a 5.2 kg object positioned 5.8 m above the ground.
GrogVix [38]

Answer:

295.568J

Explanation:

use P=mgh

plug in givens

P= 5.2*9.8*5.8= 295.568J

4 0
3 years ago
Read 2 more answers
A woman can see clearly with her right eye only when objects are between 45 cm and 155 cm away. Prescription bifocals should hav
Yuri [45]

Answer:

Explanation:

given,

A woman can see object between 45 cm and 155 cm

glasses is 2 cm from the eye

to able to read a book distance = 25 cm

For the  object distant apart

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{\infty}+\dfrac{1}{-153}

\dfrac{1}{f} = - 6.53 \times 10^{-3}

hence, D = - 0.653  m

For the object at the near point

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{23} +\dfrac{1}{-43}

\dfrac{1}{f}= 0.0202 cm

hence, D = 2.02 m

8 0
3 years ago
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