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ad-work [718]
3 years ago
9

if you are working with a radioactive source emitting particles of several kinds all positively charged not necessarily of the s

ame mass. how could you determine whether all particles have the same charge?
Chemistry
1 answer:
zlopas [31]3 years ago
3 0

Pass the charged particles at high velocity through an electric field.

The positively charged particles will deflect one way and the negatively charged particles will deflect the opposite way. The deflection will observe the Right-Hand Rule. The rate of detection will also depend on the size of the charged particle with heavier one being deflected more.


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4 years ago
2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

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Hope this helped!

Have a supercalifragilisticexpialidocious day!

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