The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
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Answer:

Explanation:
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 261.34 233.39
Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃
m/g: 75.00
1. Moles of Ba(NO₃)₂

2. Moles of BaSO₄
The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂

3. Mass of BaSO₄
