Answer:
The answer to your question is:
Explanation:
e) 9.10 x 10³ + 2.2 x 10⁶ = 2.2091 x 10⁶
f) 1113.0 - 14.6 x 10² = -347 = -3.47 x 10²
g) 6.18 x 10⁻⁴⁵ + 4.72 x 10⁻⁴⁴ = 5.338 x 10⁻⁴⁴
h) 4.25 x 10⁻³ - 1.6 x 10⁻² = -0.01175 = -1.175 x 10 ⁻²
5.- Calculate ...
a) 2.63 x 10⁻⁴
b) 2.26 x 10¹³
c) 1.97 x 10²
d) 1.65 x 10⁻²³
e) 2.5 x 10⁻⁸³
f) 1.61 x 10¹⁴
g) 2 x 10⁷⁹
h) 2.37 x 10⁻⁷
To answer this question, I need to know what the picture looks like.
Do you have more information than this
Is it a story?
You can use the follwing equations.
pH=14-pOH
pOH=-log[OH⁻]
a) pOH=-log10⁻¹²
pOH=12
pH=14-12
pH=2
You can also use these equations:
[H⁺]=K(w)/[OH⁻] (K(w)=1.01×10⁻¹⁴)
pH=-log[H⁺]
b) [H⁺]=(1.01×10⁻¹⁴)/10⁻²M
[H⁺]=1.01×10⁻¹²M²
pH=-log(1.01×10⁻¹²)
pH=12
You can use either method. It does not really matter.
I hope this helps. Let me know if anything is unclear and when you do the calculations for c you should get pH=7.
