Answer:
Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He
• molar mass of He (from the periodic table) = 4.003 g/mol
• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He
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Answer:
Height = 1.9493 cm
Width = 1.9493 cm
Depth = 1.9493 cm
Solution:
Data Given:
Mass = 20 g
Density = 2.7 g/mL
Step 1: Calculate the Volume,
As,
Density = Mass ÷ Volume
Or,
Volume = Mass ÷ Density
Putting values,
Volume = 20 g ÷ 2.7 g/mL
Volume = 7.407 mL or 7.407 cm³
Step 2: Calculate Dimensions of the Cube:
As we know,
Volume = length × width × depth
So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.
Hence,
Volume = 1.9493 cm × 1.9493 cm × 1.9493 cm
Volume = 7.407 cm³
Molar mass
C₂H₄O₂ = 60.0 g/mol
n = mass / molar mass
3.00 = mass / 60.0
m = 3.00 * 60.0
m = 180 g of <span>C₂H₄O₂
hope this helps!</span>
Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen 
if it occupies 31.6 mL at 
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature = 
As molar mass of 
is 32 g/mol. Hence, the number of moles of are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at .
Answer:
There are multiple ways to check mass but I'll tell you one. Look below
Explanation:
One easy way of checking atomic mass is by adding protons and neutrons.
For example:
We have 5 protons and 4 neutrons.
5+4=9
I hope this helps (:
