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Andrews [41]
4 years ago
11

2. What is the pH of the following solutions? 2.1. 50 mmol.dm solution of Ba(OH)2

Chemistry
1 answer:
Sphinxa [80]4 years ago
8 0

i hope this helps (please mark brainliest)

You might be interested in
Lead (II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO 3 (s) PbO (s) CO 2 (g) ________ grams of lead (I
blsea [12.9K]

Answer:

We will have 7.30 grams lead(II) oxide

Explanation:

Step 1: Data given

Mass of lead (II)carbonate = 8.75 grams

Molar mass PbCO3 = 267.21 g/mol

Step 2: The balanced equation

PbCO3 (s) ⇆ PbO(s) + CO2(g)

Step 3: Calculate moles PbCO3

Moles PbCO3 = mass / molar mass

Moles PbCO3 = 8.75 grams / 267.21 g/mol

Moles PbCO3 = 0.0327 moles

Step 4: Calculate moles PbO

For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2

For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO

Step 5: Calculate mass PbO

Mass PbO = moles PbO * molar mass PbO

Mass PbO = 0.0327 moles * 223.2 g/mol

Mass PbO = 7.30 grams

We will have 7.30 grams lead(II) oxide

7 0
4 years ago
Choose the statements below that are correct regarding the nature of protons and neutrons. Choose ALL statements that are correc
V125BC [204]

Answer:

c. protons and neutrons are found in the nucleus

d. protons and neutrons have approximately the same mass

Explanation:

There are three fundamental particles within an atom which are the protons, neutrons and electrons.

The protons are the positively charged particles within an atom

Neutrons do not carry any charges

Electrons are the negatively charged particles.

  • Both the protons and neutrons occupy the tiny nucleus at the center of the atom.
  • The electrons moves round the nucleus through the orbital space.
  • The mass of the protons and neutrons are similar and are assumed to be approximately the same.
5 0
3 years ago
Which base would not effectively deprotonate acetylene? (ch3)2nli ch3och2mgbr lioch3 ch3li kh?
Eva8 [605]

Acetylene has a chemical formula which can be written as:

C2H2

 

We can see that there are two positive ions, H+. Now what deprotonation means is that the H+ is removed from acetylene to form acetylene ion and water. In this case, I believe that the answer would be:

<span>LiOCH3</span>

8 0
3 years ago
Read 2 more answers
2.
Pepsi [2]

Answer:

0.454moles

Explanation:

Calculate the molar mass of AgBr

Ag=108

Br=80

Molar mass= 108+80

Molar mass=188g/mol

It's mole to gram question

2moles of Na2S2O3= 188g of AgBr

X moles of Na2S2O3=42.7g of AgBr

Cross multiply

188x=2×42.7

X= 85.4/188

X=0.454moles

7 0
4 years ago
A new metal alloy is found to have a specific heat capacity of 0.260 J/(g⋅∘C). First, 47 g of the new alloy is heated to 180. ∘C
Vlad1618 [11]

Answer:

The final temperature, at the equilibrium is 24.14 °C

Explanation:

Step 1: Data given

specific heat capacity of alloy = 0.260 J/(g°C)

MAss of alloy = 47 grams

Mass of water = 110 grams

Specific heat of water = 4.184 J/g°C

Initial temperature of water = 20.0 °C

Initial temperature of alloy = 180.0 °C

Step 2: Calculate the final temperature at equilibrium

Heat lost = heat gained

Qlost = -Qgained

Q(alloy) =- Q(water)

Q=m*c*ΔT

Q = m(alloy)*c(alloy)*ΔT(alloy) = -m(water) * c(water)* ΔT(water)

⇒with m(alloy) = the mass of alloy = 47.0 grams

⇒with c(alloy) = the specific heat of alloy = 0.260 J/g°C

⇒with ΔT(alloy) = the change of temperature = T2- T1 = T2 - 180 °C

⇒with m(water) = the mass of water = 110 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature = T2 - 20.0°C

47.0*0.260 * (T2 - 180.0) = - 110 * 4.184 * (T2 - 20.0)

12.22(T2-180.0) = -460.24(T2- 20)

12.22T2 - 2199.6 = -460.24T2 + 9204.8

472.46T2 = 11404.4

T2 = 24.14 °C

The final temperature, at the equilibrium is 24.14 °C

8 0
3 years ago
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