What is granite at room temperature solid liquid or gas?

An unknown compound contains only C, H, and O. Combustion of 8.50 g of this compound produced 20.0 g CO2 and 5.46 g H2O. What is

Galina-37 [17]

Answer:

The answer to your question is: C₃H₄O

Explanation:

Data

CxHyOz = 8.5 g

CO2 = 20 g

H2O = 5.46 g

Reaction

CxHyOz + O2 ⇒ CO2 + H2O

CO2

MW = 44g

44g CO2 ----------------- 12g of C

20g CO2 ---------------- x

x = (20 x 12) / 44

x = 5.45 g of C

# of moles = n = 5.45 / 12 = 0.454 mol of C

H2O

MW = 18 g

18 g H2O ------------------- 2g of H

5.46 g -------------------- x

x = (5.46 x 2) / 18 = 0.61 g of H

n = 0.61 / 1 = 0.61 moles of H2

Mass of O2

mass CxHyOz = mass CO2 + mass H2 + mass O2

mass O2 = 8.5 - 5.45 - 0.61

mass O2 = 2.44g

n = 2.44 / 16 = 0.153 mol of O2

Now, divide by the lowest number of moles

0.454 mol of C/ 0.153 = 2.97 ≈ 3

0.61 moles of H2/ 0.153 = 3.99 ≈ 4

0.153 mol of O2/ 0.153 = 1

Then, the empirical formula is: C₃H₄O

7 0

3 years ago

Which of the following models best describes the arrangement of valence electrons in metals?

Lana71 [14]

The arrangement of valence electrons in metals can be best described by the

A sea of electrons.

7 0

3 years ago

g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con

Tanzania [10]

Answer:

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

Explanation:

The equation used to calculate the constant for first order kinetics:

$t_{1/2}=\frac{0.693}{k}}$ .....(1)

Rate law expression for first order kinetics is given by the equation:

$t=\frac{2.303}{k}\log\frac{[A_o]}{[A]}$ ......(2)

where,

k = rate constant

$t_{1/2}$ =Half life of the reaction = $2.42\times 10^3 s$

t = time taken for decay process = ?

$[A_o]$ = initial amount of the reactant = 0.163 M

[A] = amount left after time t = 66.8% of $[A_o]$

[A]= $\frac{66.8}{100}\times 0.163 M=0.108884 M$

$k=\frac{0.693}{2.42\times 10^3 s}$

$t=\frac{2.303}{\frac{0.693}{2.42\times 10^3 s}}\log\frac{0.163 M}{0.108884 M}$

t = 1,409.19 s

1 minute = 60 sec

$t=\frac{1,409.19 }{60} min=23.49 min$

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

6 0

3 years ago

What is the mass percent of oxygen in Nickel (III) sulfate?

NeX [460]

The mass percent of oxygen in Nickel( $III$ )sulfate is $23.68$ percent.

At first, we look up the atomic masses for the element from the periodic table.

The atomic masses are found to be:

Ni is $58.7$
S is $32$
O is $16$

Next, we determine how many grams of each element are present in one mole of $Ni_{2}(SO_{4})_{3}$

$117.4g(2 mol*58.7)$ of Ni
$96g(3 mol*32)$ of S
$192g(12 mol * 16.00)$ of O

The mass of one mole $Ni_{2}(SO_{4})_{3}$ is:

$117.4g+96g+192g=405.4g$

So, The mass percent of oxygen $=(96g/405.4)*100=0.2368*100%\\$

$=23.68 %$ percent.

To learn more about Mass percent, refer to:

brainly.com/question/25255030

3 0

2 years ago

What is the molarity of a solution containing 7.0 moles of solute in 569 mL of solution?

yawa3891 [41]

The formula of the molarity, M is: M = number of moles of solute / Volume of solution in liters.

Here number of moles of solute is 7.0 and volume of solution in liters = 569 mL / 1000 mL/L = 0.569 L

M = 7.0 moles / 0.569 liters = 12.3 M

Answer: 12.3 M

8 0

3 years ago