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3 years ago

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Is carbon dioxide impure substance?

1 answer:

nevsk [136]3 years ago

5 0

Air is a mixture of gasses, including nitrogen, oxygen, carbon dioxide and water vapour, as such it is always chemically impure.

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The Greek letter delta (triangle sign) above the arrow in a chemical equation means.

kogti [31]

“yields” or “produces”

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3 years ago

What is the primary reason that atomic radius decreases as you move from left to right across the periodic table even through th

Anika [276]

Answer:

As you move across a period the electrons are being added to the same shell. But, protons are being added as well. This makes the nucleus more positively charged and, increasing protons has a greater effect than electrons. So, there is a greater nuclear attraction and, because the electrons are being added to the same shell that shell gets pulled in more. This causes a decrease in atomic radius.

Explanation:

5 0

3 years ago

Estimate the standard internal energy of formation of liquid methyl acetate (methyl ethanoate, ch3cooch3) at 298 k from its stan

LenKa [72]

solution:

$the reaction for formation of methyl acetate is\\CH_{3}OH+CH_{3}COOH----------->CH_{3}COOCH_{3}+H_{2}O\\standard internal energy \\\delta u=\delta H -\delta(pv)=\delta H -\delta n\times RT\\where \delta n=change in number of moles=0\\\delta u=\delta H\\=-442kj/mol$

6 0

3 years ago

Read 2 more answers

Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t

Rasek [7]

Answer:

$4.6*10^{-14}$ M

Explanation:

Concentration of $Cu^{2+} = [Cu(NO_3)_2]$ = 0.020 M

Constructing an ICE table;we have:

$Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}$

Initial (M) 0.020 0.40 0

Change (M) - x - 4 x x

Equilibrium (M) 0.020 -x 0.40 - 4 x x

Given that: $K_f =1.7*10^{13}$

$K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}$

$1.7*10^{13} = \frac{x}{(0.020-x)(0.40-4x)^4}$

Since x is so small; 0.40 -4x = 0.40

Then:

$1.7*10^{13} = \frac{x}{(0.020-x)(0.0256)}$

$1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}$

$1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x$

$8.704*10^9-4.352*10^{11}x =x$

$8.704*10^9 = 4.352*10^{11}x$

$x = \frac{8.704*10^9}{4.352*10^{11}}$

$x = 0.0199999999999540$

$Cu^{2+}= 0.020 - 0.019999999999954$

$Cu^{2+} = 4.6*10^{-14}$ M

8 0

3 years ago

How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?

Veseljchak [2.6K]

Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

$Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

$MM_{Ca(OH)_2} = 74.1g/mol$

$MM = \frac{g}{mol}$

$74.1 = \frac{35.8}{mol}\\mol = 2$

So, if there are 2 mols of Ca(OH)2:

Ca(OH)2 | H2O

$\frac{1mol}{2mol} =\frac{2mol}{xmol}$

$x = 4mol$

Finally, just find the number of grams of water using your molar mass:

$MM_{H_2O} = 18g/mol$

$18= \frac{m}{4}\\m = 72g$

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

5 0

2 years ago