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guajiro [1.7K]
3 years ago
14

The vertices of figure BCDE have coordinates B(4, 4) , C(−4, 4), D(−4, −4) , and E(4, −4) . The vertices of figure B'C'D'E' have

coordinates B'(2, 6) , C′(−6, 6), D′(−6, −2) , and E′(2, −2) . Which transformation of ​ figure BCDE ​ produces ​ figure B'C'D'E' ​ ? a translation 2 units right and 2 units down a reflection across the x-axis a translation 2 units left and 2 units up a reflection across the y-axis
Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0
The transformation used was a translation because the numbers changed. Since the x is becoming a smaller number the figure is moving to the left and since the y is getting larger the figure is also moving up. So the answer is: translation, 2 units to the left and 2 units up
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Find the slope of the line that passes through (9,3) and (6,4)​
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Slope of the line that passes through is -1/3x+6
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3 years ago
Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo
Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

y = 202 - 197.5

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3 0
3 years ago
After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the particular type of soil ide
dimaraw [331]

Answer:

The revised probabilities are;

The probability of finding soil with oil  = 0.8  

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The probability of finding medium quality oil =  0.64

Step-by-step explanation:

The given probability of finding soil with high quality oil, P(QO) = 0.20

The probability of finding soil with medium-quality oil, P(OM) = 0.80

The probability of finding soil with no oil, P(ON) = 0.2

Therefore, given that the probability of finding soil with no oil = 0.2, we have;

The probability of finding soil with oil, P(OP) = 1 - the probability of finding soil with no oil

P(OP) = 1 - 0.2 = 0.8

Which gives;

The probability, P(FG) of finding soil with oil and that the oil is good is given as follows;

P(FG) = P(QO) × P(OP) = 0.2 × 0.8 = 0.16

The probability of finding good oil = 0.16

Similarly;

The probability of finding medium quality oil P(FM) =  P(OM) × P(OP) = 0.8 × 0.8 = 0.64

Which gives the revised probability as follows;

The probability of finding soil with oil, P(OP) = 0.8  

The probability of finding soil with good oil, P(FG) = 0.16

The probability of finding medium quality oil, P(FM) =  0.64.                

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