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2 years ago

Molecules in food contain chemical energy that cells use to produce ____________________. (1 point

Chemistry

2 answers:

vladimir2022 [97]2 years ago

4 0

Molecules in food contain chemical energy that cells use to produce ATP = adenosine triphosphate.

Kipish [7]2 years ago

3 0

Answer:

Molecules in food contain chemical energy that cells use to produce Adenosine triphosphate ATP. Respiration is that the method by that cell get energy within the sort of ATP. Adenosine triphosphate captures energy obtained from the breakdown of food molecules and releases it to fuel alternative cellular processes. ATP, is that the primary carrier of energy in cells. Once energy is required by the cell, it's born-again from storage molecules into ATP.

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Match the formula to the correct name. (3 points) 1. LiClO4 2. LiCl 3. LiClO2 a. Lithium perchlorate b. Lithium chloride c. Lith

svp [43]

Answer: the answer to number 1 is a. number 2 is b. number 3 is c.

Explanation:

5 0

3 years ago

Read 2 more answers

The chief function of muscles is _____.<br> contraction<br> absorption<br> excretion<br> protection

Vilka [71]

Contraction the progress in which a muscle becomes or is made shorter and stronger :))))))))))

8 0

3 years ago

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Some COCl2 is placed in a sealed flask and heated to 756 K. When equilibrium is reached, the flask is found to contain COCl2 (7.

o-na [289]

Answer:

$9.044\times 10^{-3}$ is the value of the equilibrium constant for this reaction at 756 K.

Explanation:

$COCl_2\rightleftharpoons CO+Cl_2$

Equilibrium concentration of $COCl_2$

$[COCl_2]=7.40\times 10^{-4} M$

Equilibrium concentration of $CO$

$[CO]=3.76\times 10^{-2} M$

Equilibrium concentration of $Cl_2$

$[Cl_2]=1.78\times 10^{-4} M$

The expression of an equilibrium constant can be written as;

$K_c=\frac{[CO][Cl_2]}{[COCl_2]}$

$=\frac{3.76\times 10^{-2}\times 1.78\times 10^{-4}}{7.40\times 10^{-4}}$

$K_c=9.044\times 10^{-3}$

$9.044\times 10^{-3}$ is the value of the equilibrium constant for this reaction at 756 K.

5 0

3 years ago

If water (p=998 kg/m3, u = 10-3 Pa.s) flows through a 50 m Pa.s) determine the velocity of carbon tetrac me the velocity of carb

babymother [125]

Explanation:

As it is given that both have same dynamic characteristics.

Therefore, $Re_{water}$ = $Re_{CCl_{4}}$

$\frac{\rho_{water} \times \nu_{water} \times D_{water}}{\mu_{water}}$ = $\frac{\rho_{CCl_{4}} \times \nu_{CCl_{4}} \times D_{CCl_{4}}}{\mu_{CCl_{4}}}$

Hence, putting the given values into the above formula as follows.

$\frac{998 kg/m^{3} \times 2 m/s \times 50 mm}{10^{-3}Pa.s}$ = $\frac{1590 kg/m^{3}} \times \nu_{CCl_{4}} \times 60 mm}{0.958 \times 10^{-3}}$

$\nu_{CCl_{4}}$ = 1.002 m/s

Thus, we can conclude that the velocity of carbon tetrachloride in the given conditions is 1.002 m/s.

4 0

2 years ago

For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.

Anni [7]

Answer:

1 - Salts required that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - $CaSO_3$ (Option b) , $BaCrO_4$ (Option c) and $CaS$ (Option d)

2 - Salts that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - $Mg(OH)_2$ (Option a)

Explanation:

$K_s_p$ values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

$CuS$ {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts $CaSO_3$ , $BaCrO_4$ and $CaS$ have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

$K_s_p$ Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

2. $Zn(OH)_2$ dissociates into ions in ratio 1:2 .

Because the ions in the salt $Mg(OH)_2$ are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

Salt 2 is matched with option a.

4 0

2 years ago