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Mrrafil [7]
3 years ago
10

The small 2 next to Nitrogen is called the ____.

Chemistry
2 answers:
grandymaker [24]3 years ago
6 0

<u>Answer:</u>

<u>For 1:</u> The small 2 next to nitrogen atom is subscript.

<u>For 2:</u> The large 2 in front  of nitrogen atom is coefficient.

<u>For 3:</u> The correct answer is atoms.

<u>Explanation:</u>

Coefficients are defined as the numbers that are written in the front of atoms or molecules during a chemical reaction. They represent the number of moles of the substance present in a chemical reaction.

Subscript numbers are defined as the number of atoms of each element present in a compound.

Superscript numbers are defined as the charges of ions reacting in a chemical reaction.

  • <u>For 1:</u>

The chemical formula for nitrogen molecule given to us is N_2

Here, the small 2 next to nitrogen atom is subscript.

  • <u>For 2:</u>

The chemical formula for 2 moles of nitrogen molecule given to us is 2N_2

Here, the large 2 in front  of nitrogen atom is coefficient.

  • <u>For 3:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side. It can also be said that total number of individual atom on the reactant side is equal to the total number of individual atoms on the product side.

Hence, the correct answer is atoms.

klasskru [66]3 years ago
3 0
1. Subscript is below
2. Coefficient large 2 indicates the number of moles
3. Atoms
1/2 O2 + H2 —> H2O
It’s the atoms that balance on each side
Notes that 1/2 is the coefficient and 2 is the subscript in H2 and H2O
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Hello! Id like if someone could tell me this answer, thank you so much!
DaniilM [7]

Answer:

Option D. ZnCl₂ and H₂

Explanation:

From the question given above, the following equation was obtained:

2HCl + Zn —> ZnCl₂ + H₂

Products =?

In a chemical equation, reactants are located on the left side while products are located on the right side i.e

Reactants —> Products

Now, considering the equation from the question i.e

2HCl + Zn —> ZnCl₂ + H₂

The products are ZnCl₂ and H₂ because from our discussion above, we said that products are only located on the right side of chemical equation.

Thus, option D gives the correct answer to the question.

4 0
2 years ago
Which equation or rule can be used to estimate the pseudo-critical properties of mixtures based on the pure-component critical c
sveticcg [70]

Answer:

c. Kay's rule

Explanation:

Kay's rule -

The rule is used to determine the pseudo reduced critical parameters of mixture , with the help of using the critical properties of the components of a given mixture .

The equation for Kay's rule is as follows ,

PV = Z RT

Where Z = The compressibility factor of the mixture .

Hence from the given options , the correct answer is Kay's rule .

5 0
3 years ago
An atom with 25 protons and 27 electrons has a charge of +<br><br> True<br><br> False??
sleet_krkn [62]

Answer:

Unless you mistyped the question, the answer should be 25+

6 0
3 years ago
Automobile catalytic converters use a platinum catalyst to reduce air pollution by changing emissions such as carbon monoxide, C
julia-pushkina [17]

Answer: 448 g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} CO=\frac{784g}{28g/mol}=28moles

The balanced chemical equation is:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)  

According to stoichiometry :

2 moles of CO require  = 1 mole of O_2

Thus 28 moles of CO will require=\frac{1}{2}\times 28=14moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g

Thus 448g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

6 0
3 years ago
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Match each root with its meaning. (5 points) 1. Grad/gress 2. Ject 3. Meter 4. Junct 5. Loc a. Place b. To throw c. Measure d. T
Dima020 [189]
1. To step
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3 years ago
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