In physics<span>, a </span>force<span> is said to do </span>work if, when acting, there is a displacement of the point of application in the direction of the force. For example, when a ball is held above the ground and then dropped, the work done on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). so in the proble, <span>She does NO work since the force she applies to the case is vertical and the direction of motion is horizontal. Work is the force times the parallel distance</span>
Answer:
a = - 0.3376 g's
Explanation:
The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s
It brakes and now comes to a stop in 3.6 s.
Thus final velocity = 0 m/s
Formula for acceleration is;
a = (v - u)/t
a = (0 - (164/13.77))/3.6
a = -3.308 m/s²
In terms of g's", where 1.00 g = 9.80 m/s², we have;
a = -3.308/9.8 g's
a = - 0.3376 g's
We can answer this one very quickly. From the <em>Law of Conservation of Energy</em>, we know that "Energy can't be created or destroyed.".
So that only leaves us one way to complete the sentence in this question:
"One form of energy can be <em>transformed into</em> another type of energy.
" <em>(B)</em>
Answer:
a) A1 = 
b) A1 = 2.688 cm
c) Q1 = A1 x v1
d) v1 = 3.1994 m/s
e) A2 = 
f) A2 = 0.7963cm
Explanation:
a) Area = 
r = 
thus,
area = 
A1 = ![\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D%5B%2Ftex%3C%2Fstrong%3E%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3Eb%29%20d1%20%3D%201.85%20cm%3C%2Fp%3E%3Cp%3Esubstituting%20in%20the%20above%20equation%2C%3C%2Fp%3E%3Cp%3EA1%20%3D%20%20%5Btex%5D%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D)
A1 = 
A1 = 2.688 cm
c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)
Q1 = A1 x v1
d) From the above equation,
v1 = 
= 
= 319.94 cm/s = 3.1994 m/s
e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.
i.e. A1 x v1 = A2 x v2
thus,
A2 =
f) v2 = 10.8 m/s.
substituting the values in the above equation,
A2 = 
= 0.7963cm
Acceleration is the rate of the change in velocity.
The answer would be the rate at which velocity changes.
