The molarity of 10% CaCl2 is 0.9%
concentration of the given salt CaCl₂ = 10%
Density of a solution = 1.0835 g/cm³
Volume = m / d
= 100 / 1.0835
= 92.29 litres
Density = mass / volume
1.0835 × 92.29 = mass
mass = 99.99 gram
Thus the molarity can be calculated by = moles of solute / volume of solution multiplied by 100
= 0.9008/ 92.29 X 100 %
= 0.009 X 100 %
= 0.9 %
The molarity of 10% CaCl2 is 0.9%
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Answer:
The average induced emf in the coil is 0.0286 V
Explanation:
Given;
diameter of the wire, d = 11.2 cm = 0.112 m
initial magnetic field, B₁ = 0.53 T
final magnetic field, B₂ = 0.24 T
time of change in magnetic field, t = 0.1 s
The induced emf in the coil is calculated as;
E = A(dB)/dt
where;
A is area of the coil = πr²
r is the radius of the wire coil = 0.112m / 2 = 0.056 m
A = π(0.056)²
A = 0.00985 m²
E = -0.00985(B₂-B₁)/t
E = 0.00985(B₁-B₂)/t
E = 0.00985(0.53 - 0.24)/0.1
E = 0.00985 (0.29)/ 0.1
E = 0.0286 V
Therefore, the average induced emf in the coil is 0.0286 V
It kinda makes sense that it would be considered a metamorphosis.
When you use a wrench to tighten or loosen a nut on a bolt, you are
applying torque. It is measured in units of force times distance.
A force of F newtons pulling on a handle of L meters in length would
supply a torque of F L newton-meters.
More technically, torque is the vector cross product of force times
perpendicular distance from the object, F x r = F r sin @
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