0.56 A is the current of the secondary coil.
transformer is the device that transfer electric energy from one AC circuit to another.
we know that ;
I ∝ 1/n;
where I IS CURRENT and n is NUMBER OF TURNS.
(I) secondary = X A
(n) secondary = 100
(I) primary = 0.04 A
(n) primary = 1400
USING THIS-----> I ∝ 1/n;
=>
0.04 A/X A =100/1400
=>X=0.56 A
as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.
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