Ask question

Ask question

All categories

3 years ago

5

PLEASE HELP!!!!!!!!

1 answer:

Flura [38]3 years ago

5 0

the answer is A ,when x=0,g(x)is-1,so when u add x into the g(x),which is given below,u can find C,D,E,g(x) is no equal to -1,when you add x=1 into g(x)(A,B),you can find g(x) of B is 0,which is no equal the answer giving above(g(x)=2),but A is all right.

You might be interested in

Factor the polynomial

WARRIOR [948]

3x⁶y² + 57x⁵y³ + 252x⁴y⁴
= 3x⁴y²(x² + 19xy + 84y²)
= 3x⁴y²(x² + 12xy + 7xy + 84y²)
= 3x⁴y²(x(x + 12y) + 7y(x + 12y))
= 3x⁴y²(x + 12y)(x + 7y)

5 0

3 years ago

Devon is asked to draw a triangle with the following specifications:

N76 [4]

The answer should be c

5 0

2 years ago

Read 2 more answers

Question 7 a desk is on sale for 35% off. the sale price is $559 . what is the regular price?

marshall27 [118]

559 x 0.65 = 363.35 $

8 0

3 years ago

Write the expression using rational exponents. Then simplify and convert back to radical notation.

ioda

Answer:

The radical notation is $3x\sqrt[3]{y^2z}$

Step-by-step explanation:

Given

$\sqrt[3]{27 x^{3} y^{2} z}$

Step 1 of 1

Write the expression using rational exponents.

$\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}$

$=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}$

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0

2 years ago

In circle O, which segment is a diameter?<br><br> a) RC<br> b) SD<br> c) CO<br> d) OH

kupik [55]

RC is the diameter. As you can see, it runs across the circle.

I hope this helped you.

Brainliest answer is always appreciated.

5 0

3 years ago

Read 2 more answers