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NeTakaya
3 years ago
9

If the kinetic energy of a given mass is to be doubled, its speed must be multiplied by

Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

Either B or D. The answer itself is 2.

Explanation:

The equation for the kinetic energy would be 1/2*mv^2.

When m is doubled, we can plug in 1 and 2 to compare our answers.

Plugging in 1 for mass would give us the answer 1/2*v^2.

Plugging in 2 for mass would give us v^2. This means that the velocity was multiplied by 2, meaning that the answer is it is multiplied by 2.

I am not sure which answer is correct since there seems to be two answer choices with 2 in it, but the answer is either B or D (I will call it ABCD because I do not want to cause confusion by saying 2 multiple times).

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A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier. What i
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b) the reflected pulse returns inverted while the transmitted pulse is right side up

Explanation:

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An alpha particle collides with an oxygen nucleus, initially at rest. The alpha particle is scattered at an angle of 25.0° above
Greeley [361]

Answer:

v_{i}= 19\times 10^5\ m/s

Explanation:

given,

scattering angle of alpha particle = 25.0°  above its initial direction of motion

oxygen nucleus recoils at = 50.0° below this initial direction.

final speed of the oxygen = 2.08×10⁵ m/s

mass of alpha particle = 4.0 u

mass o oxygen nucleus = 16 u

momentum conservation along x- axis

m_{a}v_{i} = m_a v_a cos\theta + m_o v_o cos\theta

4v_{i} = 4\times v_a cos25^0 + 16\times 2.08 \times 10^5 cos50^0

v_{i}= \dfrac{3.625\times v_a+ 21.39\times 10^5}{4}....(1)

Along y-direction

0 = m_av_a sin \theta - m_ov_o sin\theta

0 = 4\times v_a sin 25 - 16\times  2.08 \times 10^5 sin50^0

v_a = \dfrac{25.49 \times 10^5}{1.69}

v_a = 15.082\times 10^5\ m/s

putting value in equation (1)

v_{i}= \dfrac{3.625\times 15.082\times 10^5+ 21.39\times 10^5}{4}

v_{i}= 19\times 10^5\ m/s

5 0
3 years ago
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