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crimeas [40]
3 years ago
15

A batter hits a foul ball. The 0.14-kg baseball that was approaching him at 40 m/s leaves the bat at 30 m/s in a direction perpe

ndicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball
Physics
2 answers:
zmey [24]3 years ago
7 0

Answer:

The magnitude of the impulse delivered to the baseball is 9.8 N s

Explanation:

Given data:

m = mass = 0.14 kg

vi = initial velocity = 40 m/s

vf = final velocity = -30 m/s

The magnitude of the impulse is equal to:

J=m(v_{i} -v_{f} )=0.14*(40-(-30))=9.8Ns

swat323 years ago
5 0

Answer:

<em>7 kgm/s or 7 Ns</em>

Explanation:

Since the velocity are perpendicular to each other, the impulses will also be perpendicular.

From newton's second law of motion,

Impulse = mass×velocity

I = mv............. Equation 1

For the horizontal,

I₁ = mv₁......... Equation 2

Given: m = 0.14 kg, v₁ = 40 m/s

Substitute into equation 2

I₁ = 40(0.14)

I₁ = 5.6 kgm/s

Also for the vertical,

I₂ = mv₂.............. Equation 3

Given: m= 0.14 kg, v₂ = 30 m/s

Substitute into equation 3

I₂ = 0.14(30)

I₂ = 4.2 kgm/s

Using Pythagoras to get the resultant impulse

I = √(I₁²+I₂²)................ Equation 4

Substitute the value of I₁ and I₂ into equation 4

I = √(5.6²+4.2²)

I = √(31.36+17.64)

I = √49

<em>I = 7 kgm/s or 7 Ns</em>

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Answer:

a) 9.72 mm

b) 4.86 mm

Explanation:

wave length of light  λ is  580 nm = 580 \times 10⁻⁹ m

Width of slit d = 0.215\times 10⁻³ m

Distance of screen D  = 1.8 m.

Width of one fringe = \frac{\lambda\times D}{d}

Putting the values we get fringe width

= \frac{580\times10^{-9}\times1.8}{.000315}

=4.86 mm.

a) Width of central maxima = 2 times width of one fringe

= 2 times 4.86

=9.72 mm

b) width of each fringe except central fringe  is same , no matter what the order is.Only brightness changes .

So width of either of the two first order bright fringe will be same and it will be  

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3 0
3 years ago
A glass prism causes dispersion or deviation but glass plate doesn't.why?​
avanturin [10]

Answer:

hope this answer helps you.

7 0
2 years ago
How much heat energy (in megajoules) is needed to convert 7 kg of ice at -9°C C to water at 0°C?
Molodets [167]

Answer:

hence option A is correct

Explanation:

heat required from -9°C to 0°C ice = mass × specific heat of ice ×change in temperature

heat required from -9°C to 0°C ice = 7×2100×9 =132300 J =0.1323 MJ

( HERE SPECIFIC HEAT OF ICE IS A CONSTANT VALUE OF 2100

J/(kg °C )

heat required from  0°C ice to 0°C water = mass× specific heat of fusion of ice

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                                                              = 2.352 × 10^6 J

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TOTAL HEAT ENERGY REQUIRED = 0.1323 MJ +2.352 MJ

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