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Rainbow [258]
3 years ago
10

Infant car seats are made to face the rear of the car. This is safer in a front end collision because of Newton's First law. New

ton's first law suggests A) Since a baby has a smaller mass it will feel a smaller force. B) The baby will move in the direction they are facing and not get throw forward. C) The baby will push on the car seat with a force equal and opposite to the own exerted on it. D) The baby will continue to move forward as the car slows and be push into the padded car seat.
Physics
2 answers:
Brut [27]3 years ago
8 0

Answer: D) The baby will continue to move forward as the car slows and be push into the padded car seat.

Explanation:

Newton's first law states that an object tends to be in state of rest or motion unless and until an unbalanced external force acts on it. This means, A body would continue to be in state of motion unless external force stops it. A body in the state of rest will remain at rest unless an external force moves it.

Infant car seat is made to face the rear of the car. This is because in case of front end collision, the car would come to sudden stop but the bodies inside the car are in state of motion and sudden halt will cause the body to push in the opposite direction.

Thus, for an infant in the car it would be a safer measure to place the seat facing the rear o the car because in this case it would cause the baby to safely collide with the padded seat of the car.

kicyunya [14]3 years ago
5 0
The answer is D hope it helps:)
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if a 60 kg person was standing on a platform at the surface of saturn and they jumped, they would have to push with a force grea
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Answer:

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The strength of gravity on the surface of Saturn = 9 N/kg

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4 0
3 years ago
A beaker of mass 1.3 kg containing 2.8 kg of water rests on a scale. A 3.7 kg block of a metallic alloy of density 4600 kg/m3 is
Oksana_A [137]

1) Force read on the upper scale: 33.4 N

2) Force read on the lower scale: 43.0 N

Explanation:

1)

The reading on the upper scale is equal to the net force acting on the block of metallic alloy. The net force is given by:

F=W-B (1)

where

W is the weight of the block (downward)

B is the buoyant force (upward)

The weight of the block is given by

W=mg

where m = 3.7 kg is the mass of the block and g=9.8 m/s^2 is the acceleration of gravity.

The buoyant force is given by

B=\rho_w V g

where

\rho_w=1000 kg/m^3 is the water density

V is the volume of the block

The volume of the block can be written as

V=\frac{m}{\rho_b}

where \rho_b=4600 kg/m^3 is the density of the block.

Substituting everything into eq.(1), we find:

F=mg-\rho_w \frac{m}{\rho_b}g=(3.7)(9.8)-(1000)\frac{1.3}{4600}(9.8)=33.4 N

2)

Here we want to find the force on the lower scale.

The force on the lower scale is equal to the difference between the total weight of the system (given by the weight of the beaker + the weight of the water + the weight of the block) and the upper net force exerted on the upper scale, therefore:

F' = m_B g + m_wg+m_b g - F

where:

m_B=1.3 kg is the mass of the beaker

m_w=2.8 kg is the mass of the water

m_b = 3.7 kg is the mass of the block

F=33.4 N is the upper net force

Substituting and solving, we find:

F'=(1.3+2.8+3.7)(9.8)-33.4=43.0 N

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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