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3 years ago

G=[(4,-6), (-9.0), (-9,-4), (-8,4)] what is the domain and range of G?

1 answer:

s2008m [1.1K]3 years ago

4 0

Hey there!
The domain and range for G are as follows:
Domain: -9, -9, -8, 4
Range: -6, -4, 0, 4
Hope this answer helps you out!

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The square root of 1000 is between

asambeis [7]

Answer:

the square root of 1000 is 31.6227766017

Step-by-step explanation:

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6 0

2 years ago

Find the area of a triangle whose sides are 5 m, 6 m and 9m,( use root 2 =-1.41 m)

dlinn [17]

The area of the triangle is 14.1 square meters

<h3>How to determine the triangle area?</h3>

The side lengths are given as:

5m, 6m and 9m

Calculate the semi-perimeter (s) using

s = (5 + 6 + 9)/2

Evaluate

s = 10

The area is then calculated as:

$Area = \sqrt{s(s -a)(s-b)(s-c)$

This gives

$Area = \sqrt{10 * (10 -5)(10-6)(10-9)$

Evaluate the products

$Area = \sqrt{200$

Evaluate the exponent

Area = 14.1

Hence, the area of the triangle is 14.1 square meters

Read more about areas at:

brainly.com/question/27683633

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4 0

2 years ago

What are the equations that have the same solutions as 3x-12=24 between

Effectus [21]

Answer:

ddqsc

Step-by-step explanation:

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5 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP !!

wariber [46]

Answer:

First figure: $954cm^3$

Second figure: $1,508yd^3$

Third figure:

Height= q
Side length = r

Fourth figure:  $726cm^3$

Explanation:

A. First figure:

1. Formula:

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

2. Data:

radius = 9cm / 2 = 4.5cm

length = 15 cm

3. Substitute in the formula and compute:

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

B. Second figure

1. Formula:

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

2. Data:

radius = 12yd

height = 40 yd

3. Substitute and compute:

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

C) Third figure

a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e. r .

When the base of the pyramid is a square the four edges of the base have the same side length.

D) Fourth figure

1. Formula

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

2. Data:

height: H = 18cm

side length of the base: 11 cm

3. Calculations

a) Calculate the area of the base.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) Volume of the pyramid:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

Read 2 more answers

4x-y=20 and -2x-2y=10

lara31 [8.8K]

You can use Substitution to solve this problem:

4x-y=20

-y=-4x+20

y=4x-20

Now you have two equations, and you use the first one to substitute into the second one.

y=4x-20 and -2x-2y=10

-2x-2(4x-20)=10

-2x-8x+40=10

-10x+40=10

-10x=-30

-x=-3

x=3

Now that we have figured out what x is, we can substitute x in to one of the equations to figure out y.

4x-y=20 x=3

4(3)-y=20

12-y=20

-y=8

y=-8

So your answer would be x=3 and y=-8

6 0

3 years ago