This problem can be seen as a rectangle triangle where the vertices are:
Vertice 1: home plate
Vertice 2: First base
Vertice 3: second base.
Right angle between vertice 1 and 2 and vertice 2 and 3.
Distance between each base in 90 '.
Calculating then the distance between home plate and second base we have:
d = root ((90) ^ 2 + (90) ^ 2)
d = 127.28 feets
answer:
the distance between home plate and second base is 127.28 feets
The length for the problem is 3
y=5/3x
this is because f(x)=x is one of (identity function) the 12 basic functions and when you multiply it it will shift it on the y axis
If you were to do y=x+5/3 it would make a horizontal shift to the left 5/3
So the unit your on is mostly about knowing the number located in the function that will make the graph shift different ways
The formula for the area of a triangle is (1/2)bh = A
when we plug in the numbers, we get (1/2)(3x-1)x = A
using the distributive property we get (1.5x - .5)x = A
Then its 1.5x^2 - .5x = A
then if we factor out 0.5x we get 0.5x(3x-1) = A
then with the zero product property, 0.5x can equal 0 and x would need to equal 0.
if 3x-1 = 0 , then 3x = 1 then x = 1/3. so our answer would be 1/3 I'm pretty sure because a length cannot be 0
