All categories

3 years ago

How many molecules of carbon monoxide are in 10 mL at STP

Chemistry

1 answer:

mote1985 [20]3 years ago

7 0

The number of carbon monoxide that are in 10 ml at STP is 2.68 x 10²⁰ molecules

calculation

Step 1 : convert 10 ml to L

convert 10 ml to L = 10/1000 =0.01 L

Step 2: find the moles of CO at STP

That is at STP 1 mole = 22.4 L

?moles = 0.01 L

by cross multiplication

= {0.01 L x 1 mole)/22.4 L} =4.46 x 10⁻⁴ moles

Step 3 ; find the number of molecules of Co using the Avogadro's law constant

that according to Avogadro's law 1 moles = 6.02 x 10²³

4.46 x 10⁻⁴ moles =? molecules

by cross multiplication

= {(4.46 x 10⁻⁴ moles) x( 6.02 x 10²³ molecules) / 1 mole} =2.68 x 10²⁰ molecules

You might be interested in

Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

Reil [10]

Answer:

The boiling point of a 8.5 m solution of Mg3(PO4)2 in water is 394.91 K.

Explanation:

The formula for molal boiling Point elevation is :

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b}$ = elevation in boiling Point

$K_{b}$ = Boiling point constant( ebullioscopic constant)

m = molality of the solution

i = Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

$Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}$

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

i = Van't Hoff Factor = 5

m = 8.5 m

$K_{b}$ = 0.512 °C/m

Insert the values and calculate temperature change:

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b} = 5\times 0.512\times 8.5$

$\Delta T_{b} = 21.76 K$

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

$\Delta T_{b} = T_{b} - T_{b}_{pure}$

$T_{b}_{pure}$ = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0

3 years ago

The density of H2O2 is 1.407 g/mL, and the density of O2 is 1.428 g/L. How many liters of O2 can be made from 55 mL H2O2

balandron [24]

Explanation:

mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g

molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2

For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).

moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2

Now, you need the temperature. If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L. Without temperature you are not really able to continue. I will assume you are at STP.

Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.

which is 53 mL.

8 0

3 years ago

What kind of energy involves the flow of positive charges

Eddi Din [679]

The kinda of energy the involves the flow of positive charge is Electrical

4 0

4 years ago

Read 2 more answers

What is happening to the protons in the nucleus and the number of orbits as you move across the periodic table from left to righ

baherus [9]

Explanation:

As you move across the periodic table, the number of protons and neutrons increases but the number of orbital levels of the period remains the same. The atomic radii therefore decrease, across the period, because the increase in proton number causes an increased pull of the orbital electrons bringing them closer to the nucleus.

As you move down a group in a periodic table, the number of orbital levels increase. The effective nuclear charge of the nucleus of the atoms decreases due to the increased number of orbital levels that shield the valence electrons from the attractive force nucleus.

6 0

3 years ago

Consider the total ionic equation below.

ZanzabumX [31]

Answer:

$\boxed{\text{Ba}^{2+}}$

Explanation:

$\rm 2H^{+} + CrO_{2}^{3-} + \textbf{Ba}^{2+} + 2OH^{-} \longrightarrow \textbf{Ba}^{2+} + CrO_{2}^{4-} + 2H_{2}O$

The spectator ions are the ions that are on both sides of the equation.

$\text{In this equation, the spectator ions are }\boxed{\textbf{Ba}^{2+}}.$

They are present at the beginning and at the end of the reaction. They don't take part in the reaction. They are simply "spectators" watching the other ions "do their thing."

3 0

3 years ago