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2 years ago

How many positive integers are in the solution set of the inequality below? -2x + 1 ≥ -6

Mathematics

2 answers:

coldgirl [10]2 years ago

7 0

Answer:

3 integers, with values: 1,2,3

Step-by-step explanation:

-2x+1>=-6

2x-1<=6

2x<=7

Positive integers: x=1,2,3

Count: 3

devlian [24]2 years ago

3 0

Answer:

3 positive integers

Step-by-step explanation:

-2x + 1 ≥ -6

-2x≥-6-1

-2x≥-7

2x≥7

Divide both sides by 2

2x/2≥7/2

x≥7/2

x≥3.5

By interpretation, it reads x greater than or equal to 3.5

That's 1, 2, 3 and even 3.5

That's 3 positive integers

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vovangra [49]

Answer:

The solutions are:

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Step-by-step explanation:

We have the following quadratic equation

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We can rewrite the equation as follows

$x^2+7x + 8=0$

Now we use the quadratic formula to solve the equation

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case:

$a=1,\ b=7,\ c=8$

Then:

$x=\frac{-7\±\sqrt{7^2-4(1)(8)}}{2(1)}$

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$x_2=\frac{-7-\sqrt{17}}{2}$

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2 years ago

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lyudmila [28]

Answer:

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Step-by-step explanation:

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Nuetrik [128]

Answer:

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