Answer:
.98m
Explanation:
Vf=Vi+2at
(V F)^2+2 ( change in distance )
X f= i ( change in V & T )
EK=1/2Mv^2,EG=mgh
The energy that the student shoud use in order to climb the stairs is equal to its increase in gravitational potential energy:
where m is the mass of the student, g the gravitational acceleration and
the variation of height. Plugging numbers into the equation, we find
The power required for the student to climb the stairs is equal to the work done divided by the time taken:
5.2m/s
Explanation:
Given parameters:
Mass of baseball = 0.15kg
Momentum of baseball = 0.78kgm/s
Unknown:
Speed of baseball = ?
Solution:
The momentum of the baseball is a function of the product of the mass and velocity. It is a vector quantity:
Momentum = mass x velocity
Since the speed of the ball is unknown:
Velocity =
=
= 5.2m/s
The speed of the baseball before it lands is 5.2m/s
Learn more:
Momentum brainly.com/question/9484203
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Answer:
a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s
Explanation:
a)
- As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
- This means that we can use the kinematic equations for displacements along both axes.
- In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:
- In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:
- For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:
b)
- From (2) we can get the position on the y-axis (displacement from the origin) as follows:
c)
- In the x- direction, we can find the component of the velocity along this direction, as follows:
- Replacing by the values, we have:
d)
- As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:
vfy = voy = -4 m/s
Answer:
The velocity and height is 31 m/s and 44.4 m respectively .
Explanation:
Given :
Initial speed of rock , u = 8.5 m/s .
Time taken to reach ground , t = 2.25 s .
Also , acceleration due to gravity is , .
Now , to find the velocity when it hit ground .
Applying equation of motion :
Also , height from which rock is thrown is given by :
Hence , this is the required solution .