Momentum will be conserved in one dimension in the explosion.
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Given that the fragment a acquires three
times the kinetic energy of the fragment b.
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P</span><span><span>initial </span><span>= p</span></span>final ⇒ 0 =mₐv⁰ₐ+mьv⁰ь= 0 ⇒ v⁰ь = -mₐv⁰ₐ/mь
KE= 3KEь
⇒1/2 mₐv⁰ₐ² = 3 (1/2mьv⁰ь²)
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⇒1/2 mₐv⁰ₐ² = 3/2 mь(-mₐv⁰ₐ/mь)²
⇒1/2 mₐv⁰ₐ² = 3/2 mь(mₐ²v⁰ₐ²/mь²)
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⇒1/2 x 2/3 = mₐ/mь= 1/3
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Thus the ratio
of the masses of the fragments is 1:3.
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8:B) Again, sound travels faster in solids
9:D) There is no particles for the sound to travel faster
10:D) The speed of light never changes the only thing that makes light change is when it travels through objects of different densities.
Answer:
(A) 0.2306 m
(B) 1.467 Hz
(C) 0.1152 m
Explanation:
spring constant (K) = 16.4 N/m
mass (m) = 0.193 kg
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) force = Kx, where x = extension
mg = Kx
0.193 x 9.8 = 16.4x
x = 0.1153 m
now the mass actually falls two times this value before it gets to its equilibrium position ( turning point ) and oscillates about this point
therefore
2x = 0.2306 m
(B) frequency (f) = \frac{1}{2π} x 
frequency (f) = \frac{1}{2π} x 
frequency = 1.467 Hz
(C) the amplitude is the maximum position of the mass from the equilibrium position, which is half the distance the mass falls below the initial length of the spring
= \frac{0.2306}{2} = 0.1152 m
the answer to your problem is work