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Ilia_Sergeevich [38]
3 years ago
14

What happens when the forces acting on an object are not balanced

Physics
2 answers:
Serjik [45]3 years ago
5 0
When two forces acting on an object are not<span> equal in size, we say that they are </span>unbalanced forces. If theforces<span> on an </span>object are unbalanced<span> this is </span>what happens<span>: an </span>object<span> that is </span>not<span> moving starts to move. an </span>object<span> that is moving changes speed or direction</span>
IRISSAK [1]3 years ago
5 0
It creates the forces to be unbalanced. The one that happens to have more force will either pull or push. This is part of Newtons second law.
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An object at rest is suddenly broken apart into fragments a and b by an explosion. the fragment a acquires three times the kinet
lbvjy [14]

Momentum will be conserved in one dimension in the explosion.

<span> Given that the fragment a acquires three times the kinetic energy of the fragment b.  
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P</span><span><span>initial </span><span>= p</span></span>final ⇒ 0 =mₐv⁰ₐ+mьv⁰ь= 0 ⇒ v⁰ь = -mₐv⁰ₐ/mь

KE= 3KEь

⇒1/2 mₐv⁰ₐ² = 3 (1/2mьv⁰ь²) 
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⇒1/2 mₐv⁰ₐ²  = 3/2 mь(-mₐv⁰ₐ/mь)²

⇒1/2 mₐv⁰ₐ²  = 3/2 mь(mₐ²v⁰ₐ²/mь²)

</span>

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<span> <span> Thus the ratio of the masses of the fragments is 1:3.    </span></span>
4 0
4 years ago
PLEASE ANSWER ALL THE QUESTIONS WILL MARK AS BRAINLIEST 20 POINTS
iogann1982 [59]
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3 0
3 years ago
A massless spring with spring constant 16.4 N/m hangs vertically. A body of mass 0.193 kg is attached to its free end and then r
svet-max [94.6K]

Answer:

(A) 0.2306 m

(B) 1.467 Hz

(C) 0.1152 m

Explanation:

spring constant (K) = 16.4 N/m

mass (m) = 0.193 kg

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) force = Kx,  where x = extension

   mg = Kx

   0.193 x 9.8 = 16.4x

   x = 0.1153 m

  now the mass actually falls two times this value before it gets to its equilibrium position ( turning  point ) and oscillates about this point

therefore

2x = 0.2306 m

(B) frequency (f) = \frac{1}{2π} x \sqrt{\frac{k}{m}}

     frequency (f) = \frac{1}{2π} x \sqrt{\frac{16.4}{0.193}}

     frequency = 1.467 Hz  

(C) the amplitude is the maximum position of the mass from the equilibrium position, which is half the distance the mass falls below the initial length of the spring

= \frac{0.2306}{2} =  0.1152 m

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3 years ago
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