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babunello [35]
3 years ago
6

99 POINTS PLEASE HELP

Physics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

The answer is C.) Work

Force is not a quantity of the transfer of energy. An example of force would be when you push on a wall. You are applying force on a wall but the wall doesn't move. Thus, there is no transfer of energy.

  • The SI unit for force is Newtons (N)

Motion is a representation of force, not a quantity of the transfer of energy. When you see a ball rolling on the ground, this is because something pushed it and applied force, or the force of gravity is pulling down on it. There is also no transfer of energy in motion.

  • The SI unit for motion is Meters Per Second (m/s)

Work is the quantity of the transfer of energy. If you were to push on a door and it opens, energy has been transferred from your arms to the door; thus, there is work present.

  • The SI unit for work is a Watt (W), or Joules per Second (j/s)

Let me know if you need any clarifications, thanks!

~ Padoru

yarga [219]3 years ago
3 0

the answer to your problem is work

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Elan Coil [88]
The average speed is (distance)/(time) = 300m / 2min. That's 150m per minute, or 2.5m per second. The average velocity is (displacement)/(time) = (distance from the start point to the end point regardless of the route)/(time)= zero.
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A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathro
choli [55]

A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathroom, kitchen, and exterior outlets is referred to as: Ground-fault interrupter.

<h3>What are arc-fault circuit interrupter?</h3>

According to "Article 100 Arc-Fault Circuit interrupter (AFCI)," arc-fault circuit interrupter is an electrical device which is designed and developed to deenergize the electrical circuit whenever it detects and recognizes characteristics unique to arcing.

Similarly, a ground-fault interrupter simply refers to an electrical device that is designed and developed for the detection of small current differences in an electrical circuit.

The main purpose of a ground-fault interrupter is to prevent electrocution or electrical shock and as such, it is an important safety measure for the following areas in a building:

  • Bathroom
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Read more on ground-fault interrupter here: brainly.com/question/12615861

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7 0
1 year ago
"A hiker starts at point P and walks 2.0 kilometers due east and then 1.4 kilometers due north. The vectors in the diagram below
Law Incorporation [45]
Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]

Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
x = 35  [ tan 35 = 0.70 ]

In short, Your Answer would be 35 degrees

Hope this helps!
3 0
3 years ago
Using diagram 1.1 and diagram 1.2, compare the number of turn of the coils, the pattern of the iron fillings and the angle of de
miss Akunina [59]

Answer:

The number of turns in the second coil is more than the coil 1.

Explanation:

The magnetic field lines are the imaginary path on which an isolated north pole moves if it is free to do so.

The tangent at any point to the magnetic field line, gives the direction of magnetic field at that point.

More be the crowd ness of magnetic field lines more is the strength of magnetic field.

Here the crowd ness of magnetic field lines is more in figure 2 , so the magnetic filed in figure 2 is more than 1. It shows that the number of turns in the second coil is more than the 1 and also the current in the coil 2 is more than 1 .

3 0
3 years ago
The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
Read 2 more answers
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