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ohaa [14]
3 years ago
6

g A mouse is sitting on top of the block in the previous question. As a reminder, the block is sliding down a ramp at a constant

speed, and the ramp is at an angle. How many forces from our list of forces in this class (ignoring air drag) are acting on the mouse at this time?
Physics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

The number of forces that are acting on the mouse will be three (Normal force, friction force and force of the mouse´s weight)

Explanation:

The number of forces that are acting on the mouse will be three. the first is the normal force acting on the midpoint of the mouse, this force is directed upward, the other is the force between the block and the bottom of the mouse, which is the friction force, and the third is the force of the mouse´s weight, which is defined as the multiplication of mass by gravity.

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Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?
Makovka662 [10]


10 x 4.186 x (30-25)=209 j
7 0
3 years ago
Read 2 more answers
14) Modify the method that calculates the sum of the integers between 1 and N. Have the new version match the following recursiv
Setler [38]

Explanation:

Let solve the program using Java programming language

Method: method means group of statements to perform some operation.

             let call the method sum.

Parameters: list of variables that are use in the method for declaration.

<u>The code</u>

public int sum (int number)

int answer;

if (number == 1)

answer = number;

else

{

int half = number/2;

int span = number - half;

answer = sum(half) + sum(span) + (half * span);

}

answer result;

}

Firstly we defined the method called sum(), the method takes only one parameter which is number and return the answer(sum of  the integers 1 and N).

if the number is equal to 1, so it will return the number and if the number is not equal to 1 it will divide the number by 2 and get the span(span used to shift upper range).And result will add sum of half, sum of span and product of half span.

8 0
4 years ago
If the potential across two parallel plates, separated by 3 cm, is 12 volts, what is the electric field strength in volts per me
Mrrafil [7]
There are 100cm in 1m, divide 100 by 3 and you get 33, multiply that by 12 and you get  396 volts/m.

Hope this is correct and helps.
6 0
4 years ago
Read 2 more answers
You are called as an expert witness to analyze the following auto accident: Car B, of mass 2100 kg, was stopped at a red light w
Artemon [7]

Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

work done by friction = 13377 x 7.30 = 97652.1 J

If v be the common velocity of both the cars after collision

kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²

= 1800 v²

so , applying work - energy theory ,

1800 v² = 97652.1

v² = 54.25

v = 7.365 m /s

This is the common velocity of both the cars .

To know the speed of car A , we shall apply law of conservation of momentum  .Let the speed of car A before collision be v₁ .

So , momentum before collision = momentum after collision of both the cars

1500 x v₁ = ( 1500 + 2100 ) x 7.365

v₁ = 17.676 m /s

= 63.63 mph .

( b )

yes Car A was crossing speed limit by a difference of

63.63 - 35 = 28.63 mph.

7 0
3 years ago
Two long, straight wires are parallel and are separated by a distance of d = 0.210 m. The top wire in the sketch carries current
love history [14]

Answer:

1.88\cdot 10^{-5} T, inside the plane

Explanation:

We need to calculate the magnitude and direction of the magnetic field produced by each wire first, using the formula

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I is the current

r is the distance from the wire

For the top wire,

I = 4.00 A

r = d/2 = 0.105 m (since we are evaluating the field half-way between the two wires)

so

B_1 = \frac{(4\pi\cdot 10^{-7})(4.00)}{2\pi(0.105)}=7.6\cdot 10^{-6}T

And using the right-hand rule (thumb in the same direction as the current (to the right), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is inside the plane

For the bottom wire,

I = 5.90 A

r = 0.105 m

so

B_2 = \frac{(4\pi\cdot 10^{-7})(5.90)}{2\pi(0.105)}=1.12\cdot 10^{-5}T

And using the right-hand rule (thumb in the same direction as the current (to the left), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is also inside the plane

So both field add together at point P, and the magnitude of the resultant field is:

B=B_1+B_2 = 7.6\cdot 10^{-6} T+1.12\cdot 10^{-5}T=1.88\cdot 10^{-5} T

And the direction is inside the plane.

3 0
3 years ago
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