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Wewaii [24]
4 years ago
13

Explain 5 factors that act as a stimulant to change.​

Physics
2 answers:
Tcecarenko [31]4 years ago
7 0

Answer: Stimulant is a factor which brings change in the environment.

Explanation:

The external factors and internal factors both can develop changes in the environment of a living being. The external factors include sunlight, weather, touch, vibration, predation and others. The internal factors include the physiological and biochemical changes in the body, emotions and mental make up.

Lunna [17]4 years ago
3 0

Answer:

Stimulant is a factor which brings change in the environment.

Explanation:

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g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor
Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

Where V = Voltage, I = current, R = resistance.

From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

assuming the voltage source remain constant

R = 2.2+R1,  and I = 1.4 A

V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

0.6R1 = 3.08

R1 = 3.08/0.6

R1 = 5.13 Ω

6 0
3 years ago
The windowpanes are___________ a. opaque b. transparent c. absorbent .
kogti [31]

Answer:

The windowpanes are- transparent.

The color of the panes are due to the wavelengths of light that the glass- allows to pass through

Explanation:

Just answered the question.

4 0
4 years ago
Read 2 more answers
A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A bloc
Nikitich [7]

Answer:

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

Explanation:

From the law of conservation of energy

Energy lost  by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr

0.5kd^{2}=0.5mv^{2}+mgLsin\theta+\mu_{k}mgcos\theta x

x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

The required distance from A to B is x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

5 0
3 years ago
A heat engine operates between a hot reservoir with a temperature of 400 K and a cold reservoir with a temperature of 300 K. The
natali 33 [55]

Answer:

Explanation:

Given

Temperature of Hot reservoir T_1=400 K

Temperature of Cold reservoir T_2=300 K

Heat reservoir Q=500 J

Work done W=150 J

heat Exhaust Q_{rejection }=350 J

Q=W+Q_{rejected}

500=150+350

L.H.S=R.H.S

thus it follows first law

\eta _{carnot}=1-\frac{T_L}{T_H}

\eta _{carnot}=1-\frac{300}{400}

\eta _{carnot}=0.25

Cycle Efficiency

\eta =\frac{W}{Q}=\frac{150}{500}=0.3

Carnot efficiency is less than cycle thus it violates second law

3 0
4 years ago
A car moved 50 km to the North. What is its displacement?
MariettaO [177]

Answer:

50 Km

Explanation:

If the car moved 50 km north and then 50 south its displacement would be 0. if it go in a direction like sw or ne or nw

4 0
4 years ago
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