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AlekseyPX
3 years ago
13

A liter is how many quarts

Mathematics
2 answers:
galben [10]3 years ago
6 0

Answer:

One liter is like 1.05668821 quarts and just round it to whatever your teacher wants

iogann1982 [59]3 years ago
4 0

Answer:

About 1.05 US quart

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SOMEONE HELP ME PLS<br><br>I ATTACHED A PIC​
crimeas [40]

Answer:

A=54.95\ ft^2

Step-by-step explanation:

The angle of shaded sector = 360-332 = 28°

The radius of sector, r = 15 ft

We need to find the area of the shaded sector. The formula for the area of the sector is given by :

A=\dfrac{\theta}{360}\times \pi r^2\\\\=\dfrac{28}{360}\times 3.14\times (15)^2\\\\A=54.95\ ft^2

So, the area of the shaded sector is equal to 54.95\ ft^2.

5 0
3 years ago
Solve for B -(12 x 2) x (-6) = -12 x (2 x b)<br> A. -6<br> B. 6<br> C. -12<br> D. 12
myrzilka [38]

<u><em>Answer:</em></u>

<u><em>Option A</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>-(12 x 2) x (-6) = -12 x (2 x b)</em></u>

<u><em>=> -24 x -6 = -12 x 2b</em></u>

<u><em>=> 144 = -24b</em></u>

<u><em>=> b = -6</em></u>

<u><em>Hoped this helped.</em></u>

5 0
2 years ago
Two kinds of crated cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200
BlackZzzverrR [31]

Answer:

The correct answer is option b)

50a+10b<1000; 200a+360b < 7200; a> 0; b>0

Step-by-step explanation:

We are given that Two kind of crated cargo namely A and B to be shipped by truck.

<u>Cargo A:</u>

Volume of each crate of cargo A = 50 cubic ft

Weight of each crate of cargo A = 200 pounds

Let number of crates of cargo A to be shipped = a

Total volume of 'a' crates of cargo A = 50a cubic ft

Total weight of 'a' crates of cargo A = 200a pounds

<u>Cargo B:</u>

Volume of each crate of cargo B = 10 cubic ft

Weight of each crate of cargo B = 360 pounds

Let number of crates of cargo B to be shipped = b

Total volume of 'b' crates of cargo B = 10b cubic ft

Total weight of 'b' crates of cargo B = 360b

Total volume allowed in the truck is 1000 cubic ft

Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

50a+10b ....... (1)

Total weight allowed (load limit) in the truck is 7200 pounds

Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

200a+360b ....... (1)

And number of crates of cargo A and B are always a positive number.

So, a > 0 and b > 0.

So, the correct answer is option b.

<em>b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0</em>

3 0
3 years ago
Hezekiel runs 1000 m at a rateof 3 minutes per km. how long does he take to run 500 m​
lana66690 [7]

Step-by-step explanation:

1 km = 1000 m

(hence the term "kilo" which means 1000).

so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.

now, we can see the solution already with our eyes.

but let's do it formally :

the rate or ratio between time and distance must be the same for the same speed.

so,

3 min / 1000 m = x min / 500 m

500 m × 3 min / 1000 m = x min

1/2 × 3 min = x min

3/2 = 1.5 min = x min

so, it takes him 1.5 minutes (90 seconds) to run 500 m.

3 0
2 years ago
Which of the following is true for f(x) = -2 sin(x) - 3?
Naddik [55]

Answer:

Step-by-step explanation:

4 0
2 years ago
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