The living things in an area interacting with their physical environment make up an ?
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Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CuCl₂: 1 mole
- NaNO₃: 2 moles
- Cu(NO₃)₂ : 1 mole
- NaCl: 2 moles
The molar mass of the compounds is:
- CuCl₂: 134.44 g/mole
- NaNO₃: 85 g/mole
- Cu(NO₃)₂ : 187.54 g/mole
- NaCl: 58.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
- NaNO₃: 2 moles ×85 g/mole= 170 grams
- Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
- NaCl: 2 moles ×58.45 g/mole= 116.9 grams
The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?
<u><em>mass of NaCl= 1.739 grams</em></u>
Finally, 1.729 grams of NaCl is formed.
Learn more about the reaction stoichiometry:
Complete question:
Write the condensed formula from left to right, starting with (CH3)x where x is a number.
See attached image for the structure formula of the compound
Answer:
(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane
Explanation:
If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.
Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).
The condensed formula will be written as;
(CH₃)₂CHC(CH₃)₃
This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane
2.) Average atomic mass =Σ (abundance x molar mass) /100
= (12.64 x 302.04 + 18.23 x 304.12 + 69.13 x 305.03) /100
=304.486 u(Dalton) . This is avg atomic mass.
