A. The kinetic energy of the food particles increased, causing the food temperature to rise.
B. The thermal energy of the food increased
Explanation:
The grilling of the meat increased the thermal energy which cause the kinetic energy of the food particles to increase thereby causing the temperature of the food to rise.
Heat is a form of energy known as thermal energy. It results from the difference in temperature between two bodies.
When a body is heated, the particles of the medium if solid as in the case of the meat begins to vibrate about their fixed point.
Temperature is directly proportional the average kinetic energy of a particle and so the particles gain more kinetic energy.
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Because it has no <span> stereogenic carbon centres.</span>
Focus your attention to the units of the given data and the unit of the final measurement you're going to solve. Through dimensional analysis,you know that the working equation would be:
Food Value = CcalΔT/m
Food value = (6.15 kJ/°C)(1.29 °C)/0.611 g = 12.98 kJ/g
Convert kJ to cal (1 kJ = 239 cal)
Food value = 12.98*239 =<em> 3,103.28 cal/g</em>
.5336
using avogadro’s law
Answer:
5. +5
6. +7
Explanation:
The oxidation state can be obtained as follow:
5. Oxidation state of oxygen, O = –2
Oxidation state of phosphorus, P =?
P3O10 = –5
3P + 10O = –5
3P + (10 x –2) = –5
3P – 20 = –5
Collect like terms
3P = –5 + 20
3P = 15
Divide both side by 3
P = 15/3
P = +5
Therefore, the oxidation state of P in P3O10^5- is +5
6. Oxidation state of oxygen, O = –2
Oxidation state of manganese, Mn =.?
Mn2O7 = 0
2Mn + 7O = 0
2Mn + (7 x –2) = 0
2Mn – 14 = 0
Collect like terms
2Mn = 14
Divide both side by 2
Mn = 14/2
Mn = +7
Therefore, the oxidation state of Mn in Mn2O7 is +7
