The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:
D
Step-by-step explanation:
If there is a 2x2 matrix as ![\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The determinant is given by ![\frac{1}{ad-bc}\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bad-bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dd%26-b%5C%5C-c%26a%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<em>Now, if we calculate the value of "ad - bc", we see that:</em>

We can't calculate the inverse, the inverse doesn't exist. The answer is D.
The answer is D, because -2/3/2 = -4/3.
Step-by-step explanation:
f×0.2 = 182 ft²
20% is a factor 0.2, as it is 20 of 100.
You did not attach any
picture to solve this problem. We cannot calculate for the value W’X’ without
the correct illustrations. However, I think I found the correct one (see
attached), please attach it next time.
So the first thing we have to
do is to calculate for the dilation factor. Taking point G as the reference
point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5
while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor
to use is:
dilation factor = 1.5 / (1.5
+ 7.5) = 1.5 / 9 = 1/6
Since WX has an initial
measure of 3 units, therefore the measure of W’X’ is:
W’X’ = 3 units * (1/6) = 0.5
units
Answer:
<span>0.5 units</span>