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dangina [55]
3 years ago
10

What is the center of a circle represented by the equation (x−5)2+(y+6)2=42? (−6,5) (−5,6) (5,−6) (6,−5)

Mathematics
1 answer:
iragen [17]3 years ago
3 0

Answer:

(5,-6)

Step-by-step explanation:

Recall that the equation for a circle is given as:

(x – h)² + (y – k)² = r²

where, the center is represented by point (h,k) and r is the radius.

IF we compare this to our given equation:

(x−5)² + (y+6)² = 42

( x−5 )²+( y-(-6) )² = 42

we see that h = 5 and k = -6

hence the center is located at (5,-6)

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