Hi there!

To find the potential energy of the ball at B, we can use the equation:
PE = mgh
Plug the given gravity, mass, and height:
PE = (1.5)(0.5)(9.8) = 7.35 J
At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:
v = √2KE/m
Plug in the solved for energy and mass:
v = √2(7.35)/1.5
Solve:
v ≈ 3.13 m/s
A. Closed. This is because the circuit can flow without interruption.
<h2>
Answer:</h2>
1.8 x 10⁻⁵J
<h2>
Explanation:</h2>
The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;
E =
x C x V² -------------------(i)
Now, from the question;
C = 2.00μF = 2.00 x 10⁻⁶F
V = 18.0V
Substitute these values into equation (i) as follows;
E =
x 2.00 x 10⁻⁶ x 18.0
E = 1.8 x 10⁻⁵J
Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J
<span>The rate at which energy is transferred is called "power."</span>