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2 years ago

Write the formula that shows the dependence of: HELP PLEASE

Mathematics

1 answer:

Arlecino [84]2 years ago

4 0

$\qquad\qquad\huge\underline{{\sf Answer}}$

$\textbf{Volume of a cube can be represented as :}$

$\textsf{ side³}$

$\textsf{And the side length is given as a}$

$\textsf{So, volume of the given cube is :}$

$\textsf{V = a³ }$

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Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

Evaluate the function for the given value: f(x)=2x (to the power of 2) -5x-17, find f(-3)

lions [1.4K]

Answer:

f(-3) = 16

Step-by-step explanation:

You substitute -3 to x.

f(-3) = 2(-3)² - 5(-3) - 17

f(-3) = 16.

As for the coordinates, the coordinates plotted in the graph above are (1,-1) and (2,-2).

7 0

3 years ago

Read 2 more answers

Santa and his elves had a workshop that allowed them to produce 22{,}912{,}546{,}99222,912,546,99222, comma, 912, comma, 546, co

zvonat [6]

Answer: 180 times

Step-by-step explanation:

Given the following :

Production capacity of old workshop :22,912,546,992 toys per year

Production capacity of new workshop:

4,134,232,638,937 toys

Approximately how many times as many toys can the new workshop produce each year compared to the old workshop?

Production capacity of new workshop / production capacity of old workshop

= 4,134,232,638,937 / 22,912,546,992

= 180.435

= 180 ( nearest whole number)

3 0

3 years ago

Use the graph of y = ex to evaluate e1.7 to four decimal places. 4.6211 2.7183 5.4739 0.1827

Gre4nikov [31]

The answer is 5.4739

3 0

3 years ago

Read 2 more answers

Solve the system of equations using the substitution method.

Firdavs [7]

y = -1 + 3/8x

2x - 5y = 6

Substitute the first equation into the second equation, since y is already by itself.

2x - 5(-1 + 3/8x) = 6

2x + 5 - 15/8x = 6

2x - 15/8x = 1

16/8x - 15/8x = 1

1/8x = 1 Multiply 8 on both sides to get x by itself

x = 8

Plug x into either of the equations.

y = -1 + 3/8(8)

y = -1 + 3

y = 2

2(8) - 5y = 6

16 - 5y = 6

-5y = -10

y = 2

(8,2)

8 0

3 years ago