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e-lub [12.9K]
3 years ago
6

A 250KG ROCKET HAS 1,953,125 JOULES OF ENERGY. HOW FAST IS ITMOVING?​

Physics
1 answer:
UNO [17]3 years ago
6 0

Answer:

cnbv gncvjhmv

Explanation:

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A ball is thrown upward from an initial height of 1.5m the ball reaches a height of 5m then falls to the ground . What Is the di
jeka94

Answer:

The distance traveled by the ball is 8.5 m

Explanation:

Initial height of the ball, h₁ = 1.5 m above the ground

final height of the ball, h₂ = 5m

Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m

Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m

Total distance traveled = upward distance + downward distance

Total distance traveled = 3.5 m + 5m = 8.5 m

Therefore, the distance traveled by the ball is 8.5 m

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Which of the following will cause a decrease in an object's weight? Increase in the mass of the object Decrease in the mass of t
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Which of the following statements is true? The square root of the molecular weight of a gas is equal to its rate of diffusion. T
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The gas diffusion rate is inversely proportional to the square root of its molecular weight.
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Can anyone explain how tides work
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A rock is thrown upward from the level ground in such a way that the maximum height of its flight is equal to its horizontal ran
marshall27 [118]

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a) For the rock

\dfrac{v_t^2sin 2\theta}{g} = \dfrac{v_t^2sin^2\theta}{2g}

2sin\thetacos\theta = \dfrac{sin^2\theta}{2}

2cos\theta = \dfrac{sin\theta}{2}

tan\theta = 4

\theta = tan^{-1} 4

\theta = 76^0

b) \theta = 45^0 for maximum range

\dfrac{d_{max}}{d}=\dfrac{(v_tcos 45^0)(2v_tsin 45^0)g}{(v_tcos 76^0)(2v_tsin 76^0)g}

\dfrac{d_{max}}{d}=\dfrac{0.707\times 0.707)}{0.97\times 0.242}

\dfrac{d_{max}}{d}=2.129

d_{max}=2.129 d

c) The value of θ is the same on every planet as g divides out.

5 0
3 years ago
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