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balandron [24]
3 years ago
13

un objeto se lanza verticalmente hacia arriba con una velocidad de 40 km/h calcular el tiempo que tarda cuando alcanza su altura

maxima
Physics
1 answer:
givi [52]3 years ago
5 0

Answer:

1.1326 seconds

Explanation:

First we can convert the speed to meter per second:

40 / 3.6 = 11.111 m/s

The gravity is given by -9.81 m/s^2.

The object will reach the maximum height when the velocity is zero, so we can use the formula:

V = Vo + a*t

Where V is the final velocity, Vo is the inicial velocity, a is the acceleration and t is the time:

0 = 11.111 - 9.81*t

9.81t = 11.111

t = 1.1326 seconds

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Answer:

0.0567 N

Explanation:

q1 = 3 micro coulomb

q2 = - 2 micro coulomb

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AB = 60 cm

By using Pythagoras theorem in triangle OAB

OA^{2}=OB^{2}+AB^{2}

OA^{2}=50^{2}+60^{2}=6100

OA = 78.1 cm

By using the Coulomb's law, the force on 3 micro coulomb due to -2 micro coulomb is

F=\frac {Kq_{1}q_{2}}{OA^{2}}= \frac{9 \times 10^{9}}\times 3\times 10^{-6} \times 2 \times 10^{-6}{0.781^{2}}

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denis23 [38]

A) a piece of wire

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