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Georgia [21]
3 years ago
11

A meteorologist tracks the movement of a thunderstorm with Doppler radar. At 8:00pm the storm was 55 mi northeast of her station

. At 11:00 pm the storm is at 75 mi north. What's the direction of the average velocity of the storm? And the magnitude of the average velocity of the storm?
Physics
1 answer:
Rus_ich [418]3 years ago
4 0
At 8:00 pm, the velocity of the storm is 55 mi northeast. Assuming that the direction is exactly northeast, the angle is 45°
At 11:00 pm, the velocity is 75 mi north. The angle is 90°
In vector form
55 ∠ 45°
and
75 ∠ 90°
The magnitude and direction of the average velocity is
(55 ∠ 45° + 75 ∠ 90° ) / 3
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What two factors affect the rate of acceleration of an object?
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For help with this answer, we look to Newton's second law of motion:

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Since the question seems to focus on acceleration, let's get
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Here's the equation again:

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Divide each side by 'mass',
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Hulk starts at -2 m, jumps to -15 m, and settles at 6 m. What is Hulk's displacement?
Lorico [155]

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6 0
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A motorboat traveling with a current can go 160 km in 4 hours. against the current it takes 5 hours to go the same distance. Fin
MatroZZZ [7]
<h2>Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.</h2>

Explanation:

Let speed of motor boat be m and speed of current be c.

A motorboat traveling with a current can go 160 km in 4 hours.

   Distance = 160 km

   Time = 4 hours

    Speed = m + c

   We have

            Distance = Speed x Time

            160 = (m+c) x 4

            m + c = 40     --------------------- eqn 1

Against the current it takes 5 hours to go the same distance.

   Distance = 160 km

   Time = 5 hours

    Speed = m - c

   We have

            Distance = Speed x Time

            160 = (m-c) x 5

            m - c = 32     --------------------- eqn 2

eqn 1 + eqn 2

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             m = 36 km/hr

Substituting in eqn 1

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Answer:

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Explanation:

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