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Georgia [21]
3 years ago
11

A meteorologist tracks the movement of a thunderstorm with Doppler radar. At 8:00pm the storm was 55 mi northeast of her station

. At 11:00 pm the storm is at 75 mi north. What's the direction of the average velocity of the storm? And the magnitude of the average velocity of the storm?
Physics
1 answer:
Rus_ich [418]3 years ago
4 0
At 8:00 pm, the velocity of the storm is 55 mi northeast. Assuming that the direction is exactly northeast, the angle is 45°
At 11:00 pm, the velocity is 75 mi north. The angle is 90°
In vector form
55 ∠ 45°
and
75 ∠ 90°
The magnitude and direction of the average velocity is
(55 ∠ 45° + 75 ∠ 90° ) / 3
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Calculate the AMA of an access ramp if it takes 255 N of force to push a person in a wheelchair having a combined weight of 764
Andreyy89
Actual Mechanical Advantage(AMA) = Weight / Force
Here, Weight = 764 N
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Substitute the values in to the expression, 
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After rounding-off to the nearest tenth value, it would be 3

Finally, option C would be your answer.

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The terminal speed acquired by the body when,

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It is given,

Drag force is directly proportional to the speed,

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Where F is drag force,

V is the speed,

C is the constant,

So, it can be written as C = F/V.

The weight of the body = mg

The weight of the body = 10m

M is the mass and g is the acceleration due to gravity,

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Now, it can be written,

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To know more about terminal speed, visit,

brainly.com/question/14605362

#SPJ4

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