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sergeinik [125]
4 years ago
15

An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 J of gravitational potential energy. How high did the hike

r climb?
Physics
2 answers:
Nataly_w [17]4 years ago
6 0

Answer:

599.5 m

Explanation:

The gain in gravitational potential energy of the man is given by:

\Delta U=mg\Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the hiket

In this problem, we have the following data:

U = 470,000 J

g = 9.8 m/s^2

m = 80 kg

Solving the formula for \Delta h, we find:

\Delta h = \frac{U}{mg}=\frac{470,000}{(80)(9.8)}=599.5 m

Alik [6]4 years ago
4 0

Answer:

600

Explanation:

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If the Sun were to turn into a black hole, or be replaced by a black hole
with the same mass as the Sun, then Earth would continue to orbit it
as usual.  (But it would be very cold and dark around here.)
3 0
4 years ago
Uses of Photodiode.State the 8 uses of phototide...................​
Inessa05 [86]

Answer:

Photodiodes are used in consumer electronics devices such as compact disc players, smoke detectors, medical devices and the receivers for infrared remote control devices used to control equipment from televisions to air conditioners. For many applications either photodiodes or photoconductors may be used.

6 0
3 years ago
A car is traveling at 104 km/h when the driver sees an accident 50 m ahead and slams on the brakes. What minimum constant decele
Solnce55 [7]

Answer:

–8.35 m/s²

Explanation:

We'll begin by converting 104 km/h to m/s. This can be obtained as follow:

3.6 Km/h = 1 m/s

Therefore,

104 km/h = 104 km/h × 1 m/s / 3.6 Km/h

104 km/h = 28.89 m/s

Thus, 104 km/h is equivalent to 28.89 m/s.

Finally, we shall determine the deceleration of the car. This can be obtained as follow:

Initial velocity (u) = 28.89 m/s

Final velocity (v) = 0 m/s

Distance (s) = 50 m

Deceleration (a) =?

v² = u² + 2as

0² = 28.89² + (2 × a × 50)

0 = 834.6321 + 100a

Collect like terms

0 – 834.6321 = 100a

–834.6321 = 100a

Divide both side by 100

a = –834.6321 / 100

a = –8.35 m/s²

Thus, the deceleration of the car is –8.35 m/s².

5 0
3 years ago
A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0
3 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0
3 years ago
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