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sergeinik [125]
3 years ago
15

An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 J of gravitational potential energy. How high did the hike

r climb?
Physics
2 answers:
Nataly_w [17]3 years ago
6 0

Answer:

599.5 m

Explanation:

The gain in gravitational potential energy of the man is given by:

\Delta U=mg\Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the hiket

In this problem, we have the following data:

U = 470,000 J

g = 9.8 m/s^2

m = 80 kg

Solving the formula for \Delta h, we find:

\Delta h = \frac{U}{mg}=\frac{470,000}{(80)(9.8)}=599.5 m

Alik [6]3 years ago
4 0

Answer:

600

Explanation:

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Answer:

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

Explanation:

Given;

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tension on the rope, T = 12 N

The acceleration of the object is calculated by applying Newton's second law of motion as follows;

T = F + W

T = ma + W

ma = T - W

a = \frac{T-W}{m} \\\\a = \frac{12 - 20}{2} \\\\a = -4 \ m/s^2 (the negative sign indicates deceleration of the object)

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2 years ago
A ball with a momentum of 16 kg.M/s strikes a ball at rest. What is the total momentum of both the balls after the collision.
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Answer:

Total momentum = 16 Kgm/s

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On your first trip to Planet X you happen to take along a 280 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
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