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2 years ago

Magnetic pole reversal worksheet

Physics

1 answer:

Likurg_2 [28]2 years ago

8 0

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The driver of a car traveling at 30.5 m/s slams on the brakes so that the car undergoes a constant acceleration, skidding to a c

dolphi86 [110]

Answer:

-6.8 m/s²

Explanation:

Given:

v₀ = 30.5 m/s

v = 0 m/s

t = 4.5 s

Find: a

a = (v − v₀) / t

a = (0 m/s − 30.5 m/s) / 4.5 s

a = -6.8 m/s²

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2 years ago

A mass that weighs 10 lb stretches a spring 2.4 in. It rests in a liquid which imparts a dampening force of 4 pounds when the ve

forsale [732]

Answer:

The solution is attached in the pictures below

Explanation:

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2 years ago

How many lines per mm are there in the diffraction grating if the second order principal maximum for a light of wavelength 536 n

grandymaker [24]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.

Constructive interference can be defined as

$dSin\theta = m\lambda$

Where

m= Any integer which represent the number of repetition of spectrum

$\lambda$ = Wavelength

d = Distance between the slits.

$\theta$ = Angle between the difraccion paterns and the source of light

Re-arrange to find the distance between the slits we have,

$d = \frac{m\lambda}{sin\theta }$

$d = \frac{2*536*10^{-9}}{sin(24)}$

$d = 2.63*10^{-6}m$

Therefore the number of lines per millimeter would be given as

$\frac{1}{d} = \frac{1}{2.63*10^{-6} }$

$\frac{1}{d} = 379418.5\frac{lines}{m}(\frac{10^{-3}m}{1 mm})$

$\frac{1}{d} = 379.4 lines/mm$

Therefore the number of the lines from the grating to the center of the diffraction pattern are 380lines per mm

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2 years ago

5. What is the frequency of a sound wave when the speed of the sound is 340 m/s and has a wavelength of 1.21 m?

LekaFEV [45]

Explanation:

v = f × /\

340 = 1.21f

f = 280.99Hz

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2 years ago

An unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of

Finger [1]

The first part of the question is:

Two point charges are placed on the x axis. (Attached file)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis.

Answer:

q3 = +0.3nc

Explanation:

Due to the vector symbols in the solution, I've decided to attach the explanation to this answer.

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2 years ago