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marshall27 [118]
3 years ago
15

Describe how the weak monoprotic acid hydrofluoric acid, HF (used in aluminum processing) acts when it is added to water, includ

ing a description of the nature of the particles in solution before and after the reaction with water. If there is a reversible reaction with water, describe the forward and the reverse reactions
Chemistry
1 answer:
grigory [225]3 years ago
3 0

Answer:

Explanation:

HF ,Hydrofluoric acid  happens to be a weak acid and as we know that a weak acid is partially dissociated in water.

So when we dissolve HF in water it would subsequently dissociate into H⁺ and F⁻ions . The solution now would contain hydronium ion that is H+ ion.

The solution would also contain dissociated F⁻ ion and solvent H20 molecules.

The following reaction would take place:

HF+H₂O⇆H₃O⁺+F⁻

so the reaction in forward direction is the dissociation of HF into H₃O⁺(that is H⁺) and F⁻ion.

The backward reaction would be the recombination of H₃O⁺(that is H⁺) and F⁻ion to give back HF and H₂O

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3 years ago
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq) , as desc
vlada-n [284]

Answer:

0.87g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

Step 2:

Data obtained from the question. This includes the following:

Volume (V) of Cl2 obtained = 235mL

Temperature (T) = 25°C

Pressure (P) = 805 Torr

Step 3:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 235mL = 235/1000 = 0.235L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 25°C

Temperature (Kelvin) = 25°C + 273 = 298K

For Pressure:

760 Torr = 1 atm

Therefore, 805 Torr = 805/760 = 1.06 atm

Step 4:

Determination of the number of mole of Cl2 produced. This is illustrated below:

The number of mole (n) of Cl2 produced can be obtained by using the ideal gas equation as follow:

PV = nRT

Volume (V) = 0.235L

Temperature (T) = 298k

Pressure (P) = 1.06 atm

Gas constant (R) = 0.082atm.L/Kmol

Number of mole (n)

PV = nRT

Divide both side by RT

n = PV /RT

n = (1.06 x 0.235)/(0.082 x 298)

n = 0.01 mole

Therefore 0.01 mole of Cl2 is produced from the reaction.

Step 5:

Determination of the number of mole MnO2 that produce 0.01 mole of Cl2. This is illustrated below:

MnO2(s) + 4HCl(aq) —> MnCl2(aq) + 2H2O(l) + Cl2(g)

From the balanced equation above,

1 mole of MnO2 produced 1 mole of Cl2.

Therefore, it will take 0.01 mole to MnO2 to also produce 0.01 mole of Cl2.

Step 6:

Converting 0.01 mole of MnO2 to grams.

This is illustrated below:

Number of mole MnO2 = 0.01 mole

Molar Mass of MnO2 = 55 + (2x16) = 87g/mol

Mass of MnO2 =?

Mass = number of mole x molar Mass

Mass of MnO2 = 0.01 x 87

Mass of MnO2 = 0.87g

Therefore, 0.87g of MnO2 is needed for the reaction.

8 0
3 years ago
What does the chemical formula cacl2 show about the compound it represents?
Anna [14]
A chemical formula that indicates the kinds of atoms and the number of each kind in a molecule of a compound.
7 0
3 years ago
Read 2 more answers
A barium hydroxide solution is prepared by dissolving 2.06 g of Ba(OH)2 in water to make 32.9 mL of solution. What is the concen
navik [9.2K]

Answer:  1.36 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

moles of solute= \frac{\text {given mass}}{\text {molar mass}}=\frac{2.06g}{171g/mol}=0.0120moles

Molarity=\frac{0.0120\times 1000}{32.9}=0.364M

The balanced reaction between barium hydroxide and perchloric acid:

2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL

Putting values in above equation, we get:

1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M

Thus the concentration of the acid is 1.36 M

4 0
3 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

The final temperature, t₂ = 30.9 °C

<h3>Further explanation</h3>

Given

24.0 kJ of heat = 24,000 J

Mass of calorimeter = 1.3 kg = 1300 g

Cs = 3.41 J/g°C

t₁= 25.5 °C

Required

The final temperature, t₂

Solution

Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

t₂ = 30.9 °C

3 0
3 years ago
Read 2 more answers
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