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3 years ago

If you detect that something’s wrong while lowering a lift, you should try to get the vehicle down as fast as possible

1 answer:

4 0

False, it depends on the situation. If the lift is tilting or anything like I would then get down. Certain training will say to get out and see if you can keep lowering,

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I really need some help here!

Virty [35]

Explanation:

<h3>1.*Frame Structure have joins which keep them together whereas Shell Structure have no joins.</h3><h3>*Shell Structure usually only support their own weight whereas Frame Structure support others weight as well as themselve.</h3>

7 0

3 years ago

Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the

siniylev [52]

Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the
path of the blade

6 0

3 years ago

Read 2 more answers

The conditions at the beginning of compression in an Otto engine operating on hot-air standard with k=1.35 and 101.325 kPa, 0.05

Katyanochek1 [597]

Answer:

$P_m=181.42 KPa$

Explanation:

$P_1=101.325 KPa,V_1=0.05m^3,T_1=32C$ ,K=1.35

Clearance is 8%.

Heat added=15 KJ

We know that compression ratio $r=1+\dfrac{1}{C}$

$r=1+\dfrac{1}{0.08}$

r=13.5

$r=\dfrac{V_1}{V_2}$

$13.5=\dfrac{0.05}{V_2}$

$V_2=3.7\times 10^{-3}$

We know that efficiency of otto cycle

$\eta =1-\dfrac{1}{r^{k-1}}$

$\eta =1-\dfrac{1}{13.5^{1.35-1}}$

$\eta =0.56$

$\eta =\dfrac{W}{Q}$

W is the work out put and Q is the heat addition.

$0.56 =\dfrac{W}{15}$

W=8.4 KJ

We know that Work =Mean effective pressure x swept volume.

Here swept volume $V_s=V_1-V_2$

$V_s=0.05-3.7\times 10^{-3}$

$V_s=0.0463 m^3$

Noe by putting the values

Work =Mean effective pressure x swept volume.

$8.4=P_m\times 0.0463$

$P_m=181.42 KPa$

6 0

3 years ago

Create a program, using at least one For Loop, that displays the Sales Amounts in each of 4 regions during a period of three mon

kari74 [83]

Answer:

C++ code explained below

Explanation:

/*C++ program that prompts sales for four regions of three sales and prints

the sales values to console */

#include<iostream>

#include<iomanip>

#include<cstring>

using namespace std;

int main()

{

//set constant values

const int SALES=3;

const int REGIONS=4;

//create an array of four regions

string regionNames[]={"Region 1","Region 2","Region 3","Region 4"};

//create a 2D array to read sales

int sales[REGIONS][SALES];

//read sales for four regions

for(int region=0;region<REGIONS;region++)

{

cout<<regionNames[region]<<endl;

for(int sale=0;sale<SALES;sale++)

{

cout<<"Enter sales ";

cin>>sales[region][sale];

}

//print sales

for(int region=0;region<REGIONS;region++)

{

cout<<regionNames[region]<<"-";

for(int sale=0;sale<SALES;sale++)

{

cout<<setw(5)<<sales[region][sale];

}

cout<<endl;

}

//pause program output on console

system("pause");

return 0;

}

5 0

4 years ago

In order to produce a certain semiconductor, a process called doping is performed in which phosphorus is diffused into germanium

Nimfa-mama [501]

Answer:

The diffusivity is given as $8.064\times 10^{-16} m^2/s$

Explanation:

From the given data as in the attached question found via the search (because the values were not clear in this one)

$D_o=2.0\times10^{-4}m^2/s\\Q_d=240.6 kJ/mol=2.406 \times 10^5 J/mol\\Gas Constant=R=8.314 J/mol K\\Temperature =830 C =830+273 =1103 K$

So the Diffusion coefficient is given as

$D=D_oe^{\frac{-Q_d}{RT}}\\D=(2.0\times 10^{-4})e^{\frac{-2.406\times 10^5}{8.314\times 1103}}\\D=8.0640\times 10^{-16} m^2/s$

So the diffusivity is given as $8.064\times 10^{-16} m^2/s$

4 0

4 years ago