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balandron [24]
3 years ago
10

What would happen if an exposed film was accidentally placed in the fixer before being placed in the developer

Engineering
1 answer:
Eduardwww [97]3 years ago
5 0
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Air enters an adiabatic gas turbine at 1590 oF, 40 psia and leaves at 15 psia. The turbine efficiency is 80%, and the mass flow
melamori03 [73]

Answer:

a) 158.4 HP.

b) 1235.6 °F.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:

m_{in}h_{in}=W_{out}+m_{out}h_{out}

Whereas the mass flow is just the same, which means we have:

W_{out}=m_{out}(h_{out}-h_{in})

And the enthalpy and entropy of the inlet stream is obtained from steam tables:

h_{in}=1860.7BTU/lbm\\\\s_{in}= 2.2096BTU/lbm-R

Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:

s_{out}= 2.2096BTU/lbm-R

Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.

Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:

h_{out}=1659.15BUT/lbm

Then, the isentropic work (negative due to convention) is:

W_{out}=2500lbm/h(1659.15BUT/lbm-1860.7BUT/lbm)\\\\W_{out}=-503,875BTU

And the real produced work is:

W_{real}=0.8*-503875BTU\\\\W_{real}=-403100BTU

Finally, in horsepower:

W_{real}=-403100BTU/hr*\frac{1HP}{2544.4336BTU/hr} \\\\W_{real}=158.4HP

Regards!

6 0
3 years ago
Why is GoPro the easiest way to capture and share your experiences?
max2010maxim [7]

Answer:

GoPro cameras have a fixed 170-degree lens. This allows for wide-angle photos and videos. Basically, at 170-degrees, it will capture almost everything in front of the camera. To get absolutely everything, it would need another 10-degrees

Explanation:

3 0
2 years ago
What is JIT and why would you advocate it to reduce inventory?
bazaltina [42]

Explanation:

Just in time inventory is a system of managing inventory. It is a method to reduce waste, lower cost and increase profit. According to it the raw material orders are directly aligned with the production schedules. In simple words every component of a unit is arriving just in time to be used.

So JIT would be advocated to reduce inventory.

7 0
3 years ago
A particular NMOS device has parameters VT N = 0.6 V, L = 0.8µm, tox = 200 Å, and µn = 600 cm2 /V–s. A drain current of ID = 1.2
NeTakaya

Answer:

W= 3.22 \mu m

Explanation:

the transistor In saturation drain current region is given by:

i_D}=K_a(V_{GS}-V_{IN})^2

Making K_a the subject of the formula; we have:

K_a=\frac {i_D} {(V_{GS} - V_{IN})^2}

where;

i_D = 1.2m

V_{GS}= 3.0V

V_{TN}  = 0.6 V

K_a=\frac {1.2m} {(3.0 - 0.6)^2}

K_a = 208.3 \mu A/V^2

Also;

k'_n}=\frac{\mu n (\frac{cm^2}{V-s} ) \epsilon _{ox}(\frac{F}{cm} ) }{t_{ox}(cm)}

where:

\mu n (\frac{cm^2}{V-s} ) = 600

\epsilon _{ox}=3.9*8.85*10^{-14}

{t_{ox}(cm)=200*10^{-8}

substituting our values; we have:

k'_n}=\frac{(600)(3.988.85*10^{-14})}{(200*10^{-8})}

k'_n}=103.545 \mu A/V^2

Finally, the width can be calculated by using the formula:

W= \frac{2LK_n}{k'n}

where;

L = 0.8 \mu m

W= \frac{2*0.8 \mu m *208.3 \mu}{103.545 \mu}

W= 3.22 \mu m

4 0
4 years ago
What is the first step in the Design Process *
Gennadij [26K]

Answer:

Define the problem

I hope this helps!

Explanation:

The problem must be know before you can develop and solution, generate concepts, or construct and test a prototype

8 0
3 years ago
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