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andrezito [222]
2 years ago
9

Do plastic materials have high or low ductility? Explain why.​

Engineering
1 answer:
Flura [38]2 years ago
3 0
The impact behavior of plastic materials is strongly dependent upon the temperature. At high temperatures, materials are more ductile and have high impact toughness. At low temperatures, some plastics that would be ductile at room temperature become brittle.
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Define factors that can change the performance of a polymer, such are additives
inna [77]

Answer:

 The performance of the polymer is basically change by the various type of factors like shape, tensile strength and color.

The polymer based products are basically influenced by the environmental factors like light, acids or alkalis chemicals, salts and also heat.

The additives is one of the type of chemical polymer which basically include polymer matrix for improving the ability of processing of the polymer. It also helps to enhance the production and requirement of the polymer products in the environment.

8 0
3 years ago
Ammonia is one of the chemical constituents of industrial waste that must be removed in a treatment plant before the waste can s
Yanka [14]

Answer:

Following is attached the solution or the question given.

I hope it will help you a lot!

Explanation:

5 0
3 years ago
Your program will be a line editor. A line editor is an editor where all operations are performed by entering commands at the co
soldier1979 [14.2K]

Answer:

Java program given below

Explanation:

import java.util.*;

import java.io.*;

public class Lineeditor

{

private static Node head;

 

class Node

{

 int data;

 Node next;

 public Node()

 {data = 0; next = null;}

 public Node(int x, Node n)

 {data = x; next =n;}

}

 

public void Displaylist(Node q)

 {if (q != null)

       {  

        System.out.println(q.data);

         Displaylist(q.next);

       }

 }

 

public void Buildlist()

  {Node q = new Node(0,null);

       head = q;

       String oneLine;

       try{BufferedReader indata = new

                 BufferedReader(new InputStreamReader(System.in)); // read data from terminals

                       System.out.println("Please enter a command or a line of text: ");  

          oneLine = indata.readLine();   // always need the following two lines to read data

         head.data = Integer.parseInt(oneLine);

         for (int i=1; i<=head.data; i++)

         {System.out.println("Please enter another command or a new line of text:");

               oneLine = indata.readLine();

               int num = Integer.parseInt(oneLine);

               Node p = new Node(num,null);

               q.next = p;

               q = p;}

       }catch(Exception e)

       { System.out.println("Error --" + e.toString());}

 }

public static void main(String[] args)

{Lineeditor mylist = new Lineeditor();

 mylist.Buildlist();

 mylist.Displaylist(head);

}

}

7 0
2 years ago
One of the most important parts about creating great photographs starts with choosing what to photograph
Sliva [168]
Yeah that is important
7 0
3 years ago
Reference Parameters (returning multiple values): Write a C++ function that converts standard time to military time. Inputs incl
valkas [14]

Answer:

Code is given as below:

Explanation:

#include <iostream>

using namespace std;

//function prototype declaration

void MilitaryTime(int, int, char, int &, int &);

int main()

{

    //declare required variables

    int SHour, SMin, MHour, MMin;

    char AorP;

    //promt and read the hours from the user

    cout<<"Enter hours in standard time : ";

    cin>>SHour;

    //check the hours are valid are not

    while(SHour<0 || SHour>12)

    {

         cout<<"Invalid hours for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter hours in standard time : ";

         cin>>SHour;

    }

    //promt and read the minutes from the user

    cout<<"Enter minutes in standard time : ";

    cin>>SMin;

    //check the minutes are valid are not

    while(SMin<0 || SMin>59)

    {

         cout<<"Invalid minutes for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter minutes in standard time : ";

         cin>>SMin;

    }

    //promt and read the am or pm from the user

    cout<<"Enter standard time meridiem (a for AM p for PM): ";

    cin>>AorP;

    //check the meridiem is valid are not

    while(!(AorP=='a' || AorP=='p' || AorP=='A' || AorP=='P'))

    {

         cout<<"Invalid meridiem for standard time. "

             <<"Try again..."<<endl;

         cout<<"Enter standard time meridiem (a for AM p for PM): ";

         cin>>AorP;

    }

    //call function to calculate the military time

    MilitaryTime(SHour, SMin, AorP, MHour, MMin);

    //fill zeros and display standard time

    cout.width(2);

    cout.fill('0');

    cout<<SHour<<":";

    cout.width(2);

    cout.fill('0');

    cout<<SMin;

    if(AorP=='a' || AorP=='A')

         cout<<" am = ";

    else

         cout<<" pm = ";

    //fill zeros and display military time

    cout.width(2);

    cout.fill('0');

    cout<<MHour;

    cout.width(2);

    cout.fill('0');

    cout<<MMin<<endl;

    system("PAUSE");

    return 0;

}

//function to calculate the military time with reference parameters

void MilitaryTime(int SHour, int SMin, char AorP, int &MHour, int &MMin)

{

    //check the meredium is am or pm

    //and calculate hours

    if(AorP=='a' || AorP=='A')

    {

         if(SHour==12)

             MHour = 0;

         else

             MHour = SHour;

    }

    else

         MHour = SHour+12;

    MMin = SMin;

5 0
3 years ago
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