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gizmo_the_mogwai [7]

3 years ago

7

Chakan worked at the warehouse after school.He earned $9.25 per hour stacking boxes.Which equation correctly relates to Chakan's

total earnings,d,to the number of hours worked,h?

1 answer:

kogti [31]3 years ago

4 0

Answer:

the answer is :the answer

Step-by-step explanation:

the answer is obvioulsy what ever the answer is,

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You need to get to class, 200 meters away, and you can only walk in the hallways at about 1.5 m/s. (if you run any faster, you’l

RUDIKE [14]

Answer:

Time = 133.3 secs

Step-by-step explanation:

<u><em>Speed = Distance / Time</em></u>

<em>Rearranging the formula</em>

Time = Distance / Speed

Where D = 200 m , S = 1.5 m/s

Time = 200 / 1.5

Time = 133.3 secs

6 0

3 years ago

Read 2 more answers

Solve Systems of Equations Algebracallyy=x+2 y=-3x

Sphinxa [80]

y = x + 2

y = -3x

Do y = -3x in y = x + 2

y = x + 2

-3x = x + 2

-3x - x = 2

-4x = 2

x = -2/4

x = -1/2

Now put x = -1/2 in y = -3x

y = -3x

y = -3.(-1/2)

y = 3/2

5 0

3 years ago

Find the surface area of the cylinder.

Ronch [10]

Answer:

exact: 48pi cm^2

approximate: 150.8 cm^2

Step-by-step explanation:

SA = 2 * (pi)r^2 + 2(pi)rh

SA = 2 * pi * (3 cm)^2 + 2(pi) * 3 cm * 5 cm

SA = pi(18 cm^2 + 30 cm^2)

SA = 48pi cm^2

SA = 150.8 cm^2

4 0

3 years ago

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A food company distributes its tomato soup in two cans of different sizes. For the larger can, the diameter has been increased b

Murrr4er [49]

Answer:

Step-by-step explanation:

buenas tardes .....

solucion

Volumen de un cilindro: es igual al área de la tapa por la altura del mismo

A = πD² * h / 4

Lata grande y lata pequeña

Para la lata grande, el diámetro y la altura han aumentado un 20%.

Lata pequeña:

d = 4 cm

h = 3 cm

A 1 = π * (4) ² * 3/4

A1 = 37,70 cm²

Lata grande:

d = 4 * 1,2 = 4,8 cm

h = 3 * 1,2 = 3,6 cm

A2 = π (4,8) ²3,6 / 4

A2 = 65,14 cm²

Si 37,7 representa el 100%

65,14 representación x

x = 170%

El incremento del volumen es de un 70%

6 0

3 years ago

Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.

barxatty [35]

Answer:

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

$\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx$

If $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ , $a = 0$ , $b = b$ and $\bar f = 8$ , then:

$\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8$

$\frac{7}{b}\int\limits^b_0 \, dx + \frac{10}{b} \int\limits^b_0 {x}\, dx - \frac{9}{b} \int\limits^b_0 {x^{2}}\, dx = 8$

$\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8$

$7 + 5\cdot b - 3\cdot b^{2} = 8$

$3\cdot b^{2}-5\cdot b +1 = 0$

The roots of this polynomial are determined by the Quadratic Formula:

$b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

7 0

3 years ago