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Dmitrij [34]
3 years ago
6

a certain car travels 20 km east then turns south for 13 km finally the car turns east again for 6 km

Physics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

Total distance

L = 39 km

total displacement

d = 29.1 km

Explanation:

Total distance moved by the car is total path length of the car

L = L_1 + L_2 + L_3

L = 20 + 13 + 6

L = 39 km

now similarly we will have

total displacement of the car towards East

x = 20 + 6 = 26 km

total displacement of the car towards South

y = 13 km

now net displacement of the car is given as

d = \sqrt{13^2 + 26^2}

d = 29.1 km

aliya0001 [1]3 years ago
7 0

a^2+b^2=c^2

20km^2+13km^2=c^2

400km^2+169km^2=c^2

23.853720...km

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3 years ago
A student moves a box across the floor by exerting 56.7 N of force and doing 195 J of
Paha777 [63]

Answer:

A. 3.4 m

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Given the following data;

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Workdone is given by the formula;

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3 years ago
John walks 1.00 km north, then turns right and walks 1.00 km east. His speed is 1.50 m/s during the entire stroll.a) What is the
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Answer:

(a) 1.414 km

(b) 1.06 m/s

Explanation:

(a) For John:

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